Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 16 of 17.
Mim said:
6 years ago
@Akshay.
1st year to 10th year= 2 Leap year(LY) + 8 ordinary year(OY)
11th to 20th= 3 LY+7 OY.
21st to 30th= 2 LY+ 8 OY.
31st to 40th= 3 LY+ 7 OY.
41st to 50th= 2 LY+ 8 OY.
51st to 60th= 3 LY+ 7 OY.
61st to 70th= 2 LY+ 8 OY.
1st to 80th= 3 LY+ 7 OY.
81st to 90th= 2LY + 8 OY.
91st to 100th year= 3 LY+ 7 OY.
In total 25 leap year and 75 ordinary years in 100 years. Here we don't count 1st year as leap year. We've counted 1st year as OY.
Then how 24 LY + 76 OY in 100 year? Please explain to me.
1st year to 10th year= 2 Leap year(LY) + 8 ordinary year(OY)
11th to 20th= 3 LY+7 OY.
21st to 30th= 2 LY+ 8 OY.
31st to 40th= 3 LY+ 7 OY.
41st to 50th= 2 LY+ 8 OY.
51st to 60th= 3 LY+ 7 OY.
61st to 70th= 2 LY+ 8 OY.
1st to 80th= 3 LY+ 7 OY.
81st to 90th= 2LY + 8 OY.
91st to 100th year= 3 LY+ 7 OY.
In total 25 leap year and 75 ordinary years in 100 years. Here we don't count 1st year as leap year. We've counted 1st year as OY.
Then how 24 LY + 76 OY in 100 year? Please explain to me.
R G said:
6 years ago
Here, for calculation of 1997, they have said 1600 yrs + 300 yrs.
So the odd day obtained is 1. But instead, if we do 1700 yrs + 200 yrs than odd days obtained will be different. How to understand this? Please explain to me.
So the odd day obtained is 1. But instead, if we do 1700 yrs + 200 yrs than odd days obtained will be different. How to understand this? Please explain to me.
ASHOK said:
6 years ago
@All.
First we need to know about century codes;
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6
Then we need to know month codes.
jan =0,feb=3, mar=3, apr=6, may=1, jun=4, july=6, aug=2, spt=5, oct=0, nvm=3, dec=5 afterv knowing this..
The finding procedure is;
Given date=28
Last two digits of the year=06
Last two digits divided by 4=1(taking the only quotient)
Century code =6.
AFTER, ADD ALL THE VALUES WE GET 42 SINCE WE HAVE 7 DAYS DIVIDE THE NUMBER 42/7=0.
Answer is SUNDAY.
First we need to know about century codes;
1600-1699=6
1700-1799=4
1800-1899=2
1900-1999=0
2000-2999=6
Then we need to know month codes.
jan =0,feb=3, mar=3, apr=6, may=1, jun=4, july=6, aug=2, spt=5, oct=0, nvm=3, dec=5 afterv knowing this..
The finding procedure is;
Given date=28
Last two digits of the year=06
Last two digits divided by 4=1(taking the only quotient)
Century code =6.
AFTER, ADD ALL THE VALUES WE GET 42 SINCE WE HAVE 7 DAYS DIVIDE THE NUMBER 42/7=0.
Answer is SUNDAY.
Shruthi said:
6 years ago
How we got 5*3? Please tell me.
Suchitra said:
6 years ago
Thanks for the clear explanation @Prabhu.
Sharath said:
6 years ago
400 years = (5 x 4 + 1).
Here 1 is added because of leap year !
Here 1 is added because of leap year !
Yashu said:
6 years ago
Anyone tell why we consider 300 & 1600 years only. Why don't we consider 400 or other than that?
Kirtan said:
6 years ago
How many leap years are there between1701 and 1900 (both included) ?
Dream boy said:
6 years ago
How to know a day of a particular date?
Dream boy said:
6 years ago
How to know a day of a particular date?
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