Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 14 of 17.
Abhi said:
8 years ago
One other way of Finding the Answer is :
Just remember that 1st Jan 2000 was Saturday.
1999 (not leap year so 365 days) = 52 weeks + 1 day.
So to go to 1st Jan 1999 just have to subtract that 1 Extra day which is bringing the change.
Just remember that 1st Jan 2000 was Saturday.
1999 (not leap year so 365 days) = 52 weeks + 1 day.
So to go to 1st Jan 1999 just have to subtract that 1 Extra day which is bringing the change.
Gardas Anusha said:
8 years ago
In 100 years isn't this correct:
25 leap years + 75 ordinary years?
4*1=4 .. 4*2=8.. 4*3=12.. ......... 4*25=100 and so 25 leap years.
25 leap years + 75 ordinary years?
4*1=4 .. 4*2=8.. 4*3=12.. ......... 4*25=100 and so 25 leap years.
Hemant said:
8 years ago
Sir, how you concluded 2 odd days from 121? Please explain me.
Nitin Gupta said:
8 years ago
Anyone explain why 144025036146 is the codes for month explain how 1 arrives for January for ordinary year and 4 for feb again 4 for March I know 31/7=3 is code for feb leap year but why 144 for jan feb march.
Kunal more said:
8 years ago
How to calculate leap year in 100 years?
Zemanian said:
8 years ago
There's a better way to solve this:
We know that for 2000 years, the number of odd days is 0.
Consider 17 June, 2001.
for the previous 2000 years, there are 0 odd days.
for the year of 2001, starting from Jan
31+28+31+30+31+17 = 168
which means there are 0 odd days.
now the day of the week for 17 June 2001 is Sunday.
now we need the day for 17 June 1998. Simply subtract the odd days of the preceding three years.
2000 is a leap year, whereas 1999 and 1998 are ordinary years.
So 0 - 2 - 1 - 1 = -4.
Go back 4 days from Sunday and you get Wednesday.
We know that for 2000 years, the number of odd days is 0.
Consider 17 June, 2001.
for the previous 2000 years, there are 0 odd days.
for the year of 2001, starting from Jan
31+28+31+30+31+17 = 168
which means there are 0 odd days.
now the day of the week for 17 June 2001 is Sunday.
now we need the day for 17 June 1998. Simply subtract the odd days of the preceding three years.
2000 is a leap year, whereas 1999 and 1998 are ordinary years.
So 0 - 2 - 1 - 1 = -4.
Go back 4 days from Sunday and you get Wednesday.
Ayesha said:
8 years ago
Why it's needed to calculate odd days for 1600 and 300?
Anuradha said:
7 years ago
How to calculate ordinary year and leap years in one century?
Please explain?
Please explain?
JOY said:
7 years ago
Simple , leap year = 100 / 4 = 25.
Ordinary year = 100 - 25 = 75.
Ordinary year = 100 - 25 = 75.
Savanth said:
7 years ago
If you want to find number of odd days in 100 years, then 100/4=25.(Only. Quotient) Now,( 100 +25)/7=6(remainder).
So, there are 6 odd days in 100 no of Years.
So, there are 6 odd days in 100 no of Years.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers