Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 13 of 17.
Sreejith s s said:
9 years ago
Read important formula of calendar problem, that time you will be realized.
Mohit said:
9 years ago
@ Sri Harsha.
Can you apply that trick on example Like 2002, 2014?
Can you apply that trick on example Like 2002, 2014?
Karthik babu said:
9 years ago
It should be 23 leap years know because 2000 is also leap year.
Khushi said:
9 years ago
Why we are considering odd days for 300 years? Can we consider 400 year instead of 300 year than odd days also changes.
Manoj kumar majhi said:
9 years ago
Find out the day in the date of 25 .5.1975.
Sayali said:
9 years ago
@Vikram.
How did you find month codes?
How did you find month codes?
Ekowseegar said:
9 years ago
How do find the odd days in 1999?
Akash Anand said:
9 years ago
The answer should be Thursday not Wednesday because there are 3 odd days.
If there had been 2 odd days then answer would have been Wednesday.
Monday + 3 odd days = Thursday.
If there had been 2 odd days then answer would have been Wednesday.
Monday + 3 odd days = Thursday.
Ramya said:
8 years ago
@Ekowseegar.
1999 can be written as 1600+300+99.
No. of odd days in 1600 years is 0.
No. of odd days in 300 years is 1.
Now, no.of leap years in 99 years is 99/4 = 24.
No. of non leap years is 99 - 24 is 75.
Extra days=(24 * 2 + 75)
= 48 + 75 = 123.
Odd days in 123 is the reminder of 123/7 that is 4.
Therefore total no of odd days = 0 + 1 + 4 = 5.
1999 can be written as 1600+300+99.
No. of odd days in 1600 years is 0.
No. of odd days in 300 years is 1.
Now, no.of leap years in 99 years is 99/4 = 24.
No. of non leap years is 99 - 24 is 75.
Extra days=(24 * 2 + 75)
= 48 + 75 = 123.
Odd days in 123 is the reminder of 123/7 that is 4.
Therefore total no of odd days = 0 + 1 + 4 = 5.
Kavitha said:
8 years ago
How 1600 and 300 come? Please give me the suggestion to solve it.
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