Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 12 of 17.
Bharathi said:
7 years ago
Can anybody derive and say 15th June 1998 is what day? Please
Deekshitha said:
2 years ago
How we can find odd days? Anyone, please help me to get this?
(9)
Likitha said:
10 years ago
Why should we consider 1600 and 300 years of odd days here?
Suba said:
4 years ago
Could anyone explain me why are we considering 300 years? .
(2)
Krishnoshakawat said:
9 years ago
Why will we calculate from 1600?
Anybody, please help me.
Anybody, please help me.
Raza said:
2 years ago
Here, 17 + 5 + 98 + 24 = 144/7 = remainder 4 {wednesday].
(12)
Ekta said:
1 decade ago
Thank you Arya. I can understand properly your solution.
Santhosh said:
1 decade ago
How to calculate number of odd days for 2008, 2009, 2010?
Sathesh said:
9 years ago
100 years are not coming Tuesday or Thursday or Saturday.
Vissu said:
9 years ago
Please explain everything ones how has come to Wednesday.
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