Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 13 of 17.
Venkatesh said:
1 decade ago
How did you calculate number of odd days for 97 years?.
Ayesha said:
8 years ago
Why it's needed to calculate odd days for 1600 and 300?
Suhel said:
7 years ago
@Rajesh.
Can you please explain how get the year code.
Can you please explain how get the year code.
Shyni said:
9 years ago
How to calculate the number of odd days in 300 years?
Sreeja said:
7 years ago
Why should we take 1600 and 300 here? Please explain.
Pratik chudasama said:
9 years ago
The answer should be Tuesday. Please check it again.
Jala said:
5 years ago
98 is a leap year then February has 29 days right?
Bidhya said:
9 years ago
What is odd day? I don't understand to find this.
Praveen said:
1 decade ago
Please tell me how 0 odd days for 400 years ?
Janvi said:
1 decade ago
How you got ordinary days? could you explain?
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