Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 11 of 17.
Sharath said:
6 years ago
400 years = (5 x 4 + 1).
Here 1 is added because of leap year !
Here 1 is added because of leap year !
Ramya said:
1 decade ago
How to calculate no.of leap years in given years? Ex. 87 years.
Priya singh said:
1 decade ago
300 years 5*3 = 15 odd days.
What is 5 and 3. Please tell me ?
What is 5 and 3. Please tell me ?
Dharsinipriya said:
1 decade ago
How to calculate leap year and ordinary year between 200 years?
Surya said:
10 years ago
I can understand that problem. So please explain simple to way?
Karthik babu said:
9 years ago
It should be 23 leap years know because 2000 is also leap year.
Srimant said:
9 years ago
How month code comes like;
J0, F3, M3, A6, -----, O0, N3, D5?
J0, F3, M3, A6, -----, O0, N3, D5?
Sonali said:
9 years ago
How did you know that Feb has 28 days regarding above example?
Hemant said:
8 years ago
Sir, how you concluded 2 odd days from 121? Please explain me.
Surya said:
10 years ago
I cannot understand our calculation so please say simple way.
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