Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 10 of 17.
Kirtan said:
6 years ago
How many leap years are there between1701 and 1900 (both included) ?
Saurabh said:
10 years ago
1998 was the leap year so the February month of 1998 has 1 odd day?
Mohit said:
9 years ago
@ Sri Harsha.
Can you apply that trick on example Like 2002, 2014?
Can you apply that trick on example Like 2002, 2014?
Vani Arora said:
3 years ago
I cannot get the answer. Anyone help me to get the answer clearly.
(8)
Chetan said:
1 decade ago
I am not understand problem correctly. Please anybody explain me.
Anupama said:
1 decade ago
Wy we are 300 years and why we are calculating odd days for 300 ?
Kavitha said:
8 years ago
How 1600 and 300 come? Please give me the suggestion to solve it.
JOY said:
7 years ago
Simple , leap year = 100 / 4 = 25.
Ordinary year = 100 - 25 = 75.
Ordinary year = 100 - 25 = 75.
Shagun pachisia said:
5 years ago
How we calculate no of leap years in 97 years? Please explain me.
Aman said:
4 years ago
Hi,
I don't understand about 1600 and 300 years, please explain.
I don't understand about 1600 and 300 years, please explain.
(8)
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