Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 9 of 17.
Karan said:
9 years ago
Can you help me in calculating? How many odd days in 50 years? Need it asap!
Zafar Ali said:
3 years ago
The output of = years (date (2016, 5, 1), date (2013, 5, 1), 0) will return.
(3)
Sreejith s s said:
9 years ago
Read important formula of calendar problem, that time you will be realized.
Radhika said:
1 decade ago
How do we calculate for 75years it is 18 leap years +57 ordinary years ?
Steffy said:
1 decade ago
To Nitin:
Here we have 97 yrs
97/4=24 leap yrs
97-24=73 ordinary yrs
Here we have 97 yrs
97/4=24 leap yrs
97-24=73 ordinary yrs
RAJESH said:
9 years ago
Is there is any shortcut way and simple way to resolve the above query?
Arun said:
1 decade ago
How to calculate odd days for 300 years? I don't understand this only.
Praveen kumar said:
1 decade ago
How we gat an idea to take 1600 years and 300 years in above problem.
Ravi said:
1 decade ago
Why you taken 300 years ? why not 400 years please explain in detail.
Rishi said:
1 decade ago
Ishan , Arya and Raviteja
Thanks to all u for ur such a explanation
Thanks to all u for ur such a explanation
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