Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 1 of 13.
T Prashanth said:
7 months ago
2008-2 odd days-leap year.
2009-1 odd days.
2010-1 odd days.
2011-1 odd days.
2012-2 odd days-leap year.
2013-1 odd days.
2014-1 odd days.
2015-1odd days.
2016-2 odd days - leap year
2017-1 odd days.
2018-1 odd days.
Up to total odd days 14,
So 1 week = 7days
so 14/7 = 0.
The zero comes 14th odd day of the 2018 year
So the answer is 2018.
Here, 2012 also get sum = 7
So 1 week = 7 days,
So 7/7=0.
2009-1 odd days.
2010-1 odd days.
2011-1 odd days.
2012-2 odd days-leap year.
2013-1 odd days.
2014-1 odd days.
2015-1odd days.
2016-2 odd days - leap year
2017-1 odd days.
2018-1 odd days.
Up to total odd days 14,
So 1 week = 7days
so 14/7 = 0.
The zero comes 14th odd day of the 2018 year
So the answer is 2018.
Here, 2012 also get sum = 7
So 1 week = 7 days,
So 7/7=0.
(6)
Riya said:
1 year ago
@All.
Why won't 2014 be considered as its sum be 21 odd days then 21/3 = remainder being 0 or 2014 - 2007.
So 7yrs + 0 odd day.
=>7/ 7 = 0
Hence 2014 could also be the same year? right?
Why won't 2014 be considered as its sum be 21 odd days then 21/3 = remainder being 0 or 2014 - 2007.
So 7yrs + 0 odd day.
=>7/ 7 = 0
Hence 2014 could also be the same year? right?
(12)
Ghanshyamraut said:
2 years ago
Take different between 2007 and 2018.
2007 - 2018 = 11+3(odd day)=14 which is exactly divided by 7.
The reminder is 0.
So, 2007 is the same will be as 2018.
2007 - 2018 = 11+3(odd day)=14 which is exactly divided by 7.
The reminder is 0.
So, 2007 is the same will be as 2018.
(8)
Akshay chouhan said:
2 years ago
Only divide the year by 4 if the remaining is 0 then add 28 in years if the remaining is 1 then add 6.
And if it is 2/3 then add 11 so 2007/4 we get 3 as a remainder.
So we add 11 in the year.
The answer is 2007+11 = 2018.
And if it is 2/3 then add 11 so 2007/4 we get 3 as a remainder.
So we add 11 in the year.
The answer is 2007+11 = 2018.
(43)
Raja said:
2 years ago
@Krishna.
Please explain it clearly.
Please explain it clearly.
(13)
Krushna said:
2 years ago
To find the total number of odd days.
Divide the total given days by 7 and it's remainder shows odd days.
Then, Maximum number of odd days is 6.
Divide the total given days by 7 and it's remainder shows odd days.
Then, Maximum number of odd days is 6.
(4)
Dev said:
3 years ago
@All
Given;
Year +6
2007+6=2013.
Find out how many leap year there in between 2007 and 2013.
there is 2008 and 2012 (2 Leap year).
If there is 2 Leap year then add 11 to the given question. It will be your answer.
2007+11 = 2018.
Instead of;
If there will be 1leap year while adding 6 in given question the answer will be given year +6= answer.
If in question there will be Leap year. Then add +5 it will be your answer.
Given;
Year +6
2007+6=2013.
Find out how many leap year there in between 2007 and 2013.
there is 2008 and 2012 (2 Leap year).
If there is 2 Leap year then add 11 to the given question. It will be your answer.
2007+11 = 2018.
Instead of;
If there will be 1leap year while adding 6 in given question the answer will be given year +6= answer.
If in question there will be Leap year. Then add +5 it will be your answer.
(5)
Ravi Maurya said:
3 years ago
This solution is not correct.
Rule:- 1.
If there are 2 leap years in 5 normal years then we can observe the same date and day.
Rule:- 2.
If there is not 2 leap years in 5 normal years then there is 1 leap year in 6 years then we can observe the same date and day.
Rule:-3.
If there is not even 1 leap year in 5 years and 6 years, then we can celebrate the same date and day after 11 years.
Rule:- 1.
If there are 2 leap years in 5 normal years then we can observe the same date and day.
Rule:- 2.
If there is not 2 leap years in 5 normal years then there is 1 leap year in 6 years then we can observe the same date and day.
Rule:-3.
If there is not even 1 leap year in 5 years and 6 years, then we can celebrate the same date and day after 11 years.
(4)
Sonu kumar said:
3 years ago
@All.
Divide the given no by 4 if remainder is 0 add 28 to the year if remainder is 1 add 6 or if remainder is 2or3 add 11, in this case, the remainder is 3.
So, 2007 + 11 = 2018.
Divide the given no by 4 if remainder is 0 add 28 to the year if remainder is 1 add 6 or if remainder is 2or3 add 11, in this case, the remainder is 3.
So, 2007 + 11 = 2018.
(30)
Mesfin said:
3 years ago
Why start count odd number fron 2008 & why not start from 2007?
Please explain me.
Please explain me.
(3)
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