Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 11)
11.
The calendar for the year 2007 will be the same for the year:
Answer: Option
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Discussion:
121 comments Page 2 of 13.
Rama said:
4 years ago
Thank you for explaining @Prasad.
Mithilesh Mahatha said:
4 years ago
@All.
So, doubt here is how 14 = 0,
See,
No of days in a week is 7.
In 14 we can make to weeks,
14/7 completely divides no remainder.
Therefore 0 odd days.
All multiple of 7 will gives 0 odd days..
So, doubt here is how 14 = 0,
See,
No of days in a week is 7.
In 14 we can make to weeks,
14/7 completely divides no remainder.
Therefore 0 odd days.
All multiple of 7 will gives 0 odd days..
(2)
Vigneshwaran said:
4 years ago
Thanks for explaining @Prasad.
Suraj said:
5 years ago
Why 2014 cannot be the answer. There are 7 odd days. Which sum up again to 0 odd days?
(1)
Shivam Padmani said:
5 years ago
Short trick for solving.
One has to divide the given year by Four.
If :
Remainder = 1 Then Add or Subtract 6 years in given years.
Remainder = 2 or 3 Then Add or Subtract 11 years in given years.
Remainder = 0 Then Add or Subtract 28 years in given years.
One has to divide the given year by Four.
If :
Remainder = 1 Then Add or Subtract 6 years in given years.
Remainder = 2 or 3 Then Add or Subtract 11 years in given years.
Remainder = 0 Then Add or Subtract 28 years in given years.
(7)
Aniket said:
5 years ago
Then, What is the solution for 2008?
Anyone explain to me.
Anyone explain to me.
Gireesh kumar said:
5 years ago
@Kunal.
See, what is the remainder after dividing the year by 4. If the remainder is 1 add 5 years to the given year. If the remainder is 2 add 11 to the given year. If the remainder is 3 adding 11 to the given year. So in the above question, they gave 2007. After dividing by 4. It gives the remainder as 3. So simply add 11 years to 2007. That will be 2018.
Hope it helps you.
See, what is the remainder after dividing the year by 4. If the remainder is 1 add 5 years to the given year. If the remainder is 2 add 11 to the given year. If the remainder is 3 adding 11 to the given year. So in the above question, they gave 2007. After dividing by 4. It gives the remainder as 3. So simply add 11 years to 2007. That will be 2018.
Hope it helps you.
(5)
Kunal said:
5 years ago
How the odd days taken here?
Meghana said:
5 years ago
Ordinary year = 1odd day.
Leap year = 2odd days.
They told to fïnd oud same calendar as 2007, so we should start counting an odd day from 2008,
2008-2odd day
2009-1odd day
2010-1odd day
2011-1odd day
2012-2odd day
Add the above odd days. To get same calendar odd days should be multiple of 7. 7 divided by 7 gives reminder 0. Hence 2012 is the answer.
Leap year = 2odd days.
They told to fïnd oud same calendar as 2007, so we should start counting an odd day from 2008,
2008-2odd day
2009-1odd day
2010-1odd day
2011-1odd day
2012-2odd day
Add the above odd days. To get same calendar odd days should be multiple of 7. 7 divided by 7 gives reminder 0. Hence 2012 is the answer.
Mandakranta said:
5 years ago
2009 was repeated in 2015.
2009 - 1 odd day
2010 - 1 (2)
2011 - 1 (3)
2012 - 2 (5)
2013 - 1 (6)
2014 - 1 (7)
So 2015 is the answer.
Again 2009 being non-leap year if we divide by 4 we get a remainder 1. So 2009 + 11= 2020 which is not possible 2020 being a leap year. So 2009 +6 =2015 is the repeated the year of 2009.
2009 - 1 odd day
2010 - 1 (2)
2011 - 1 (3)
2012 - 2 (5)
2013 - 1 (6)
2014 - 1 (7)
So 2015 is the answer.
Again 2009 being non-leap year if we divide by 4 we get a remainder 1. So 2009 + 11= 2020 which is not possible 2020 being a leap year. So 2009 +6 =2015 is the repeated the year of 2009.
(1)
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