Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
101 comments Page 10 of 11.
Bharani said:
5 years ago
Same question but find the wife age means how to solve?
Mayuri khode said:
5 years ago
@Bharani.
Instead of addition W+C you can replace it by H+C.
i.e (H+W+C)-(H+C).
Instead of addition W+C you can replace it by H+C.
i.e (H+W+C)-(H+C).
Varshithtunuguntla said:
5 years ago
Your answer is correct. Thanks @Ramya.
Manoj Kumar said:
5 years ago
@Varshithtunuguntla.
How obtained here 90 and 40. How did the multiplication?
Can you tell me?
How obtained here 90 and 40. How did the multiplication?
Can you tell me?
(3)
Ruthra said:
4 years ago
Wonderful explanation, thanks @Ramya.
(5)
Rupesh Kumar Yadav said:
3 years ago
Sum of the present ages of H,W and C = 27 + 3 = 30 So, 30 * 3 = 90Years.
Sum of the present ages of H,W and C = 20 + 5 = 25 So, 25 * 2 = 50Years.
Hence,
Husband of presents age = (90-50)years.
= 40Years.
Sum of the present ages of H,W and C = 20 + 5 = 25 So, 25 * 2 = 50Years.
Hence,
Husband of presents age = (90-50)years.
= 40Years.
(53)
Srihari said:
2 years ago
H + W + C = 27 + 3 = 30(3 years),
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
(34)
Dptt said:
2 years ago
{(H+W+C)/3} -3 = 27 [(-3) is for 3 years ago].
(H+W+C)/3=30.
H+W+C=90 ---> eqn (1)
{(W+C)/2} -5 = 20 [(-5)is for 5 years ago]
(W+C)/2= 25.
W+C=50 ------> eq(2)
Substitute eq(2) in eq(1),
H+50 =90
so, H = 40 years.
(H+W+C)/3=30.
H+W+C=90 ---> eqn (1)
{(W+C)/2} -5 = 20 [(-5)is for 5 years ago]
(W+C)/2= 25.
W+C=50 ------> eq(2)
Substitute eq(2) in eq(1),
H+50 =90
so, H = 40 years.
(29)
Saimadhav Thottala said:
2 years ago
Husband + Wife + Child = 27 (years) + 3 (years ago) => 30 x 3 (Members) => 90 years.
And;
Wife + Child = 20 (years) + 5 (years ago) => 25 x 2 (Members) => 50 years.
So,
Husband of present age = ( 90-50 )years.
= 40 years.
And;
Wife + Child = 20 (years) + 5 (years ago) => 25 x 2 (Members) => 50 years.
So,
Husband of present age = ( 90-50 )years.
= 40 years.
(87)
Shubhanshu said:
2 years ago
3 years ago, the average age of H+W+C was 27.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)
5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.
The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)
5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.
The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
(34)
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