Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 5)
5.
The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
Answer: Option
Explanation:
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
Video Explanation: https://youtu.be/ceg2jvHsiJU
Discussion:
85 comments Page 2 of 9.
Saravanan said:
7 years ago
Let x be an average of 8 persons.
Let y be the weight of the new person.
(x+y-65)/8 = (x/8)+2.5,
x+y-65 = x+20,
y-65 = 20,
y = 85.
Let y be the weight of the new person.
(x+y-65)/8 = (x/8)+2.5,
x+y-65 = x+20,
y-65 = 20,
y = 85.
(4)
Mounika said:
3 years ago
Age of captain = 26 ...
So the age of the wicket-keeper who is 3 years older than the captain = 29
Let avg of 11 members be x, then
The sum of observations /11 = x.
I. e 26+29+ remaining sum of 9 members = 11x.
Remaining sum of 9 = 11x-55--->(1)
Given that, avg of the remaining 9 will be one less than the total average.
So total avg is x, then the of 9 is x-1.
I. e sum of remaining 9/9 = x-1.
Sum of remaining 9 = 9x-9 ----> (2)
9x-9 = 11x-55 from 1 and 2.
11x -9x = -9+55.
2x = 46,
x= 46/2 = 23.
So the age of the wicket-keeper who is 3 years older than the captain = 29
Let avg of 11 members be x, then
The sum of observations /11 = x.
I. e 26+29+ remaining sum of 9 members = 11x.
Remaining sum of 9 = 11x-55--->(1)
Given that, avg of the remaining 9 will be one less than the total average.
So total avg is x, then the of 9 is x-1.
I. e sum of remaining 9/9 = x-1.
Sum of remaining 9 = 9x-9 ----> (2)
9x-9 = 11x-55 from 1 and 2.
11x -9x = -9+55.
2x = 46,
x= 46/2 = 23.
(3)
Roshni Shaji said:
9 years ago
Hai @Likha,
The question is very clear. it says. a person of 65 kg left and a new comer joined.
Average = (total sum of the scores) divided by No. of scores.
Sum of all persons (including 65 kg weighing person)/8 = X(average).
Sum of weight of 7 persons = 8X - 65 ------------------(1)
When joined another who weighs N, average increased by 2.5 kg
ie (sum of 7 person's weight + N) / 8 = X +2.5,
From (1) we get (8X - 65 + N) / 8 = X + 2.5,
8X - 65 + N = 8 *(X+ 2.5),
8X - 65 + N = 8X + 20,
N = 8X + 20 - 8X + 65,
N = 20 + 65,
N = 85.
The weight of new comer is 85 kg. the answer
The question is very clear. it says. a person of 65 kg left and a new comer joined.
Average = (total sum of the scores) divided by No. of scores.
Sum of all persons (including 65 kg weighing person)/8 = X(average).
Sum of weight of 7 persons = 8X - 65 ------------------(1)
When joined another who weighs N, average increased by 2.5 kg
ie (sum of 7 person's weight + N) / 8 = X +2.5,
From (1) we get (8X - 65 + N) / 8 = X + 2.5,
8X - 65 + N = 8 *(X+ 2.5),
8X - 65 + N = 8X + 20,
N = 8X + 20 - 8X + 65,
N = 20 + 65,
N = 85.
The weight of new comer is 85 kg. the answer
(3)
Ramu Bhandari said:
2 years ago
Here;
2 +1/2 Means 5/2.
a = 65+8* 5/2.
a = 85 is the new person's weight.
2 +1/2 Means 5/2.
a = 65+8* 5/2.
a = 85 is the new person's weight.
(3)
Koteswararao chimmili said:
9 years ago
The average weight of 8 person's increases by 2.5 kg.
Assume 8 persons.
a, b, c, d, e, f , g, h then,
(a + b + c + d + e + f + g + h)/8 = x + 2.5
(a + b + c + d + e + f + g + h = 8 ( x + 2.5)
= 8x + 20 -----------> 1
When a new person comes in place of one of them weighing 65 kg
then
(a + b + c + d + e + f + g + h + 65)/9 = x
(a + b + c + d + e + f + g + h + 65) = 9 x
(a + b + c + d + e + f + g + h= 9x - 65 -------------> 2
Solving eguation1 and 2
8x + 20 = 9x - 65.
20 + 65 = 9x - 8x.
85 = x.
Assume 8 persons.
a, b, c, d, e, f , g, h then,
(a + b + c + d + e + f + g + h)/8 = x + 2.5
(a + b + c + d + e + f + g + h = 8 ( x + 2.5)
= 8x + 20 -----------> 1
When a new person comes in place of one of them weighing 65 kg
then
(a + b + c + d + e + f + g + h + 65)/9 = x
(a + b + c + d + e + f + g + h + 65) = 9 x
(a + b + c + d + e + f + g + h= 9x - 65 -------------> 2
Solving eguation1 and 2
8x + 20 = 9x - 65.
20 + 65 = 9x - 8x.
85 = x.
(1)
Bhanu said:
1 decade ago
Hai Friends.
Try this method.
New person weight =Replaced person weight+ (no. Of persons*increased weight).
Replaced person weight =65.
No. Of persons =8.
Increased weight =2.5.
These all values are replaced in the formula, then we get the answer "85".
Try this method.
New person weight =Replaced person weight+ (no. Of persons*increased weight).
Replaced person weight =65.
No. Of persons =8.
Increased weight =2.5.
These all values are replaced in the formula, then we get the answer "85".
(1)
Fahad Riaz said:
7 years ago
Total weight of 8 persons is 520 (65*8).
Now, a total weight of 7 persons is 455 (520-65),
Now try every option to get 2.5% increase,
(455+85)/8 is equal to 67.5,
The total increase is 2.5 KG (67.5-65),
Ans is 85 KG.
Now, a total weight of 7 persons is 455 (520-65),
Now try every option to get 2.5% increase,
(455+85)/8 is equal to 67.5,
The total increase is 2.5 KG (67.5-65),
Ans is 85 KG.
(1)
Hemanjali T said:
5 years ago
Can you guys tell me about what happens if the weight is decreased by 2.5 kg? Please explain.
(1)
M rajoo said:
10 years ago
Thank you @All, for the explanation.
Rasiga said:
10 years ago
There is very simple formula for this.
Weight of New person = No of Persons * Increased weight + Replaced.
So, 8 * 2.5 + 65 = 85.
Weight of New person = No of Persons * Increased weight + Replaced.
So, 8 * 2.5 + 65 = 85.
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