Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 5)
5.
The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
76 kg
76.5 kg
85 kg
Data inadequate
None of these
Answer: Option
Explanation:

Total weight increased = (8 x 2.5) kg = 20 kg.

Weight of new person = (65 + 20) kg = 85 kg.

Video Explanation: https://youtu.be/ceg2jvHsiJU

Discussion:
84 comments Page 9 of 9.

Vineela reddy said:   1 decade ago
@Manoj kumar is it useful for all?

Please give the clear information I'm ok but little confused.

Mukesh said:   1 decade ago
Old School method.

Let Z+65 be weight of 8 person and their average be A.

So, (z+65)/8 = A .......(i).

Now with the replacing the person with 65 KG weight with new person, average becomes A+2.5, let the weight of new person be x KG.

So, (Z+x/8) = A+2.5 .......(ii).

Subtraction (i) from (ii).

(x+65)/8 = 2.5.

Therefor, x = 85.

Jay said:   1 decade ago
In this case problems you people just recall this formula:

N - R = (+ or -)nx.

N - new items added.
R - removed items.
n - average of the sum.
x - decrease or increase.

Put + when increase.
- for decrease.

Now see:
N - 65 = + 8(2.5).
N = 85.

Ganesh raw said:   1 decade ago
Guys it's simple.

Let consider the first case:

The average weight of 8 people be x.
So,
(a+b+c+d+e+f+g+65)/8=x : ( one of the person weighs 65)
=>a+b+c+d+e+f+g+65=8x .........(1).

If the person who weighs 65kg was replaced the average.
i.e. Let the new person weight be Z.

=>(a+b+c+d+e+f+g+Z)/8= x+2.5. :( the average increased by 2.5).
=> (a+b+c+d+e+f+g+Z)=8x+20 ..........(2).

From (1) =>. a+b+c+d+e+f+g+8x= -65 ..........(3).
From(2) =>. a+b+c+d+e+f+g+8x= -z + 20.........(4).

Compare (3) & (4).

-Z+20= -65.
Z= 85 kg.

Is the answer.


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