Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 15)
15.
A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half (1/2). The number of pupils in the class is:
10
20
40
73
Answer: Option
Explanation:

Let there be x pupils in the class.

Total increase in marks = x x 1 = x
2 2

x = (83 - 63)    x = 20      x= 40.
2 2

Discussion:
126 comments Page 5 of 13.

Deepak said:   8 years ago
Let avg.+1/2 = y+83/x- ------> eq1.
Y=remaining student's marks.
X =total no of students.

Now avg.= y+63/x-----> eq2
Eq2-eq1.
83-63/x=1/2.
X=40.

Mudit said:   8 years ago
I didn't understand why we are multiplying x with 1/2? Please tell me.

Royal said:   8 years ago
Nice explanation @Nik.

Ashwini said:   8 years ago
See the difference 83 and 63, which means extra 20 marks they have given. It increased by 1/2 means we shoud divide 20 by 1/2 which is nothing but 40.

Sheik said:   8 years ago
Thanks @Ravi.

Arushi Mathur said:   8 years ago
Let x = total no of students, y=Avg of students when 63 is taken.

Sum of students when 63 is taken=xy.
So, (xy-63+83) /x=y+0.5.
(xy-20) =xy-0.5x.
x = 40.

Bharat Gupta said:   8 years ago
When 63 is entered the let avg is x.

x = (sum of the marks of rest of students+63)/n.
Let the sum of the marks of rest of the students=y.
Therefore, x=(y+63)/n.

When 83 is entered avg is increased by 1/2 or 0.5.
So, x+0.5= (y+83)/n.
Equating both the terms we get;
0.5=20/n.
Therefore, n=40.

Kush said:   8 years ago
I am not getting it. Please someone explain to me briefly.

Ashok said:   8 years ago
Please explain me, I am not getting this.

Yash said:   8 years ago
Thank you @Nik.


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