Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 10)
10.
In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
Answer: Option
Explanation:
Let Arun's weight by X kg.
According to Arun, 65 < X < 72
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
 Required average = |
 |
66 + 67 + 68 |  |
= | |
201 | |
= 67 kg. |
| 3 | 3 |
Discussion:
58 comments Page 3 of 6.
Ashish said:
9 years ago
There is not mentioned that >= means 66+67/2 = 66.5.
So, answer is none of these.
So, answer is none of these.
Harika said:
9 years ago
Nice explanation thank you @Jasmine.
Abhay said:
9 years ago
67 is not the correct answer.
The correct answer is 66.5.
(65+68)/2=66.5
So the correct answer is option E.
The correct answer is 66.5.
(65+68)/2=66.5
So the correct answer is option E.
NitishPandey said:
8 years ago
@Anwi.
Son and father average age =11x+5x in linear sequence 11x is father and 5x is son,
11x+5x=40 so,
(11x+5x)=40 * 2 because here only possibility of two person father and son,
16x=80,
x=5.
Then son age = 5 * 5
So ans 25,
Hope you understand.
Son and father average age =11x+5x in linear sequence 11x is father and 5x is son,
11x+5x=40 so,
(11x+5x)=40 * 2 because here only possibility of two person father and son,
16x=80,
x=5.
Then son age = 5 * 5
So ans 25,
Hope you understand.
Abdul Waheed said:
8 years ago
You are right, Thanks @Gopal.
Jaya priya said:
8 years ago
Well explained, thank you @Jasmine.
Kiran Labade said:
7 years ago
Let's Arun weight be x.
Limit in between:
1st Arun : 65 < x < 72,
2nd Brother: 60 < x < 70,
3rd Mother : 68 < = x.
Therefore, for possible values average of each approximate values
65 + 72 = 137 /2 = 68.5 (Lower Limit + Upper limit)/2,
60 + 70 = 130 / 2 = 65,
0 + 68 = 68.
Total average ages are 68.5+65+68 = 201.5.
for three limit values hence divide by three = 201.5/3 = 67.16 (float value).
we get a float value 67.16 it is complete a boundary of 67 but not a complete boundary of 68 or 69.
Hence, the approximate value of Answer is 67 kg. [A]
Limit in between:
1st Arun : 65 < x < 72,
2nd Brother: 60 < x < 70,
3rd Mother : 68 < = x.
Therefore, for possible values average of each approximate values
65 + 72 = 137 /2 = 68.5 (Lower Limit + Upper limit)/2,
60 + 70 = 130 / 2 = 65,
0 + 68 = 68.
Total average ages are 68.5+65+68 = 201.5.
for three limit values hence divide by three = 201.5/3 = 67.16 (float value).
we get a float value 67.16 it is complete a boundary of 67 but not a complete boundary of 68 or 69.
Hence, the approximate value of Answer is 67 kg. [A]
Prateek bhaiya said:
9 years ago
Acccording to me,
Given condition : x > 65 & amp; x < 72(according to Arun opinion).
x > 60 & x < 70(according to Arun's brother).
x < = 68(according to Arun's mother).
So, average age = 65 + 72 + 60 + 70 + 68/5.
335/7 = 67.
Ans is 67.
Given condition : x > 65 & amp; x < 72(according to Arun opinion).
x > 60 & x < 70(according to Arun's brother).
x < = 68(according to Arun's mother).
So, average age = 65 + 72 + 60 + 70 + 68/5.
335/7 = 67.
Ans is 67.
Yazdani said:
7 years ago
Arun's opinion between 65 to 72 kg.
So avg of Arun's opinion= 66+67+68+69+70+71÷ 6 = 68.5 --> 1
Aruns bro opinion btwetween 60 to 70kg.
Avg =61+62+63+64+65+66+69 ÷ 7 = 65 --> 2.
Arun's opinion is 68 --> 3.
Take the avg of eq 1,2,3.
We get 67.
So avg of Arun's opinion= 66+67+68+69+70+71÷ 6 = 68.5 --> 1
Aruns bro opinion btwetween 60 to 70kg.
Avg =61+62+63+64+65+66+69 ÷ 7 = 65 --> 2.
Arun's opinion is 68 --> 3.
Take the avg of eq 1,2,3.
We get 67.
Utkarsh Patil said:
7 years ago
Why did anyone not take probable weights from 65.1 to 67.9?
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