Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 10)
10.
In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
Answer: Option
Explanation:
Let Arun's weight by X kg.
According to Arun, 65 < X < 72
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
 Required average = |
 |
66 + 67 + 68 |  |
= | |
201 | |
= 67 kg. |
| 3 | 3 |
Discussion:
58 comments Page 6 of 6.
Venu said:
1 decade ago
Guys,
If the given numbers are in A.P and no. of. numbers is odd number, then average of the whole is just the middle term or the average of first and last numbers.
E.g:- Average of 66, 67 and 68 is 67 only.
No need to do 66+67+68/3.
Use above formula and quickly answer it.
If the given numbers are in A.P and no. of. numbers is odd number, then average of the whole is just the middle term or the average of first and last numbers.
E.g:- Average of 66, 67 and 68 is 67 only.
No need to do 66+67+68/3.
Use above formula and quickly answer it.
Hemanth Kothuru said:
10 years ago
Weight can also be non integer so given answer is definitely wrong. So the possible way considering all of them are correct is 65<w<68.
So minimum weight is 65+x (x is very very small) and maximum weight is 68. So therefore average weight is 66.5.
So minimum weight is 65+x (x is very very small) and maximum weight is 68. So therefore average weight is 66.5.
Muneer said:
10 years ago
Can anyone explain in a simple way?
Vasan said:
9 years ago
@Venu, explained very well.
Ashwini madne said:
9 years ago
According to Arun, 65 < X < 72.
[(65 + 72/2) = 68.5 ie 69].
According to Arun's brother, 60 < X < 70.
[(60 + 70/2) = 65].
According to Arun's mother, X <= 68.
Required Average = (69 + 65 + 68)/3.
= 202/3.
= 67.33 i.e 67kg ==> answer.
[(65 + 72/2) = 68.5 ie 69].
According to Arun's brother, 60 < X < 70.
[(60 + 70/2) = 65].
According to Arun's mother, X <= 68.
Required Average = (69 + 65 + 68)/3.
= 202/3.
= 67.33 i.e 67kg ==> answer.
Rajeshwari said:
9 years ago
Thank you @Sathiya.
Thiruppathy said:
9 years ago
@Anwi,
The answer is 133. Am I right?
The answer is 133. Am I right?
Pavan said:
2 decades ago
How did take 66, 67 and 68 ?
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