Aptitude - Average - Discussion

His mother's view is that his weight cannot be greater than 68 kg
but she cant said that >=68
so the solution is 66+67/2=133/2=66.5
answer is none of these..

I got ans like tis way..., may i dont know whether is it correct r nt
view of arun avg=(65+72)/2=68.5
view of his brothers avg=(60+70)/2=65
view of his mother taken as=68
Therefore the avg of above three as=(68.5+65+68)/3=67

Arun says that his age is > 65 but < 72
Therefore his age in between 66 to 71.

View of his brother, Arun's age is >60 but < 70,
Therefore Arun's age in between 61 to 69.

View of his mother, Arun's age is Cannot be > 68,
That means Arun's age under 68 years only.


The above three members opinions Arun's age in in between 66 years to 68 years,

Then (66+67+68)/3.

65 - 72 -(1) : 68.5.

60 - 70 -(2) : 65.0.

68 -(3) : 68.0.
-------
201.5/3 = 67.

Logic Concept:

Let Arun age is X.
In Arun's opinion: 65 > X < 72.
Possibilities: 66, 67, 68, 69, 70, 71.

In Brother's opinion: 60 > X < 70.
Possibilities: 61, 62, 63, 64, 65, 66, 67, 68, 69

In Mother's opinion: X <= 68.
Possibilities: 1, 2, 3......61, 62, 63, 64, 65, 66, 67, 68.

Now check what similar terms are matching in every 3-possibilities i.e 66, 67, 68.

To find Average age = (66+67+68)/3.

Note: 3 = Three possible values. It is not Arun+Brother+Mother at all.

Why aren't we assuming fractional values?

There is not mentioned that >= means 66+67/2 = 66.5.

So, answer is none of these.

Guys,

If the given numbers are in A.P and no. of. numbers is odd number, then average of the whole is just the middle term or the average of first and last numbers.

E.g:- Average of 66, 67 and 68 is 67 only.

No need to do 66+67+68/3.

Use above formula and quickly answer it.

Weight can also be non integer so given answer is definitely wrong. So the possible way considering all of them are correct is 65<w<68.

So minimum weight is 65+x (x is very very small) and maximum weight is 68. So therefore average weight is 66.5.

Can anyone explain in a simple way?