Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 10)
10.
In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
67 kg.
68 kg.
69 kg.
Data inadequate
None of these
Answer: Option
Explanation:

Let Arun's weight by X kg.

According to Arun, 65 < X < 72

According to Arun's brother, 60 < X < 70.

According to Arun's mother, X <= 68

The values satisfying all the above conditions are 66, 67 and 68.

Required average = 66 + 67 + 68 = 201 = 67 kg.
3 3

Discussion:
58 comments Page 2 of 6.

Kshitij Gupta said:   7 years ago
The answer of the question is wrong as it is based upon the assumption that the weight has integral values only which is not stated anywhere in the question.

The correct solution would be as follows:
Arun's opinion: 65-72
Brother's opinion: 60-70
mother's opinion: <68.

Therefore to find the average of the all probable weights of Arun we take the average of the lower and the upper limits:

Average of lower limits: (65+60)/2 = 62.5.
Average of upper limits: (72+70+68)/3 = 70.
Therefore the average of the possible weights of Arun would then be the middle most value of this range hence: Average of all probable weights = (62.5 + 70)/2 = 66.25 (ANS).
(2)

Mithun said:   7 months ago
Best and easiest explanation. Thank you, @ANUKA.
(1)

Ankit said:   7 years ago
If it is greater than and less than why don't we take x+65 and x-70?
(1)

Supon sam said:   6 years ago
Thanks for explaining @Vinod and @Jasmine.
(1)

Gopal said:   1 decade ago
Arun-65+72/2=68.50
brother-60+70/2=65.00
mom- 68.00
total
=201.50/3= 67
(1)

Sakshi said:   1 decade ago
Can anyone explain it in another way? Please.
(1)

Madhu said:   6 years ago
@All.

Once Ajay went to the office of ROCK LINE COURIER with 4 different envelopes. The clerk in the office measured the weights in all possible pairs. The weights obtained are 59gm, 61gm, 62gm, 63gm, 64gm and 66gm. What is the weight of the heaviest envelope?

Can anyone solve it?
(1)

Rohit said:   7 years ago
There was not given any condition to consider weights as integer values.

Why take 66, 67 & 68 only?

Well, If he's greater than 65, And what he thinks is correct. He can weight, for instance, 65.1 or maybe 65.2.

Someone help me out here.

Mandeep said:   9 years ago
Thanks Prateek for clear solution.

Rahul said:   9 years ago
We can do like that

56 + 72 + 60 + 70 + 68 = 335.
335 ÷ 5 = 67 answer.


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