Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 15)
15.
A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Rs. 456
Rs. 458
Rs. 558
Rs. 568
Answer: Option
Explanation:

Area to be plastered = [2(l + b) x h] + (l x b)
= {[2(25 + 12) x 6] + (25 x 12)} m2
= (444 + 300) m2
= 744 m2.

Cost of plastering = Rs. 744 x 75 = Rs. 558.
100

Discussion:
24 comments Page 2 of 3.

Siva said:   1 decade ago
What is the formula if it is a room and need to plaster four walls, bottom and top as well ?

Ranjith said:   1 decade ago
Usually tank's shape is cylindrical and bottom is circle. Why we are taking rectangle?

Ashu said:   1 decade ago
For convinience the formula should be 2(lb+bh+hl)-area of the top which is lb

Avijit.AD said:   6 years ago
Thanks, @Salman.

That explanation is really easy to understand.

Sivaprasad said:   9 years ago
I agree with you @Sundar.

I think what he said is right @All.

Malar said:   1 decade ago
For walls its enough [2(l+b)] . Then why you multiply with h ?

Abc said:   1 decade ago
How you know the bottom is rectangular or may be any other?

Syed said:   1 decade ago
instead of the fomula [2(l + b) x h] we can write 4(l*h)

Ben said:   7 years ago
Why are we dividing 75 by 100? Please explain me.

MAS said:   8 years ago
Thanks A lot, @Salman. Your method is easiest.


Post your comments here:

Your comments will be displayed after verification.