Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 15)
15.
A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Answer: Option
Explanation:
Area to be plastered | = [2(l + b) x h] + (l x b) |
= {[2(25 + 12) x 6] + (25 x 12)} m2 | |
= (444 + 300) m2 | |
= 744 m2. |
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744 x | 75 | ![]() |
= Rs. 558. |
100 |
Discussion:
24 comments Page 2 of 3.
Siva said:
1 decade ago
What is the formula if it is a room and need to plaster four walls, bottom and top as well ?
Ranjith said:
1 decade ago
Usually tank's shape is cylindrical and bottom is circle. Why we are taking rectangle?
Ashu said:
1 decade ago
For convinience the formula should be 2(lb+bh+hl)-area of the top which is lb
Avijit.AD said:
6 years ago
Thanks, @Salman.
That explanation is really easy to understand.
That explanation is really easy to understand.
Sivaprasad said:
9 years ago
I agree with you @Sundar.
I think what he said is right @All.
I think what he said is right @All.
Malar said:
1 decade ago
For walls its enough [2(l+b)] . Then why you multiply with h ?
Abc said:
1 decade ago
How you know the bottom is rectangular or may be any other?
Syed said:
1 decade ago
instead of the fomula [2(l + b) x h] we can write 4(l*h)
Ben said:
7 years ago
Why are we dividing 75 by 100? Please explain me.
MAS said:
8 years ago
Thanks A lot, @Salman. Your method is easiest.
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