Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 15)
15.
A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Rs. 456
Rs. 458
Rs. 558
Rs. 568
Answer: Option
Explanation:

Area to be plastered = [2(l + b) x h] + (l x b)
= {[2(25 + 12) x 6] + (25 x 12)} m2
= (444 + 300) m2
= 744 m2.

Cost of plastering = Rs. 744 x 75 = Rs. 558.
100

Discussion:
24 comments Page 1 of 3.

Mahesh said:   2 decades ago
Why (l x b) is there again?

Krishna said:   1 decade ago
i agree with mahesh plastering is done to the tank perimeter not area.... this is not filling water , which occupies area it is similar to fencing the rectangular field..

so i think area to be plastered is the perimeter
2(l+b)*h...

Sundar said:   1 decade ago
@All

The cost of plastering its 'walls' and 'bottom'.

Finding area:

For walls = [2(l + b) x h]

For bottom = (l x b)

So, total area to be plastered = [2(l + b) x h] + (l x b)

I think you got it.

Ashu said:   1 decade ago
For convinience the formula should be 2(lb+bh+hl)-area of the top which is lb

Syed said:   1 decade ago
instead of the fomula [2(l + b) x h] we can write 4(l*h)

Malar said:   1 decade ago
For walls its enough [2(l+b)] . Then why you multiply with h ?

Divya said:   1 decade ago
Formula for four walls is 2(l+b)*h so we have to multiply by h this is for four walls but here it is given as tank so v huv to cover the bottom area also so (l*b).

Hence to find we have to add both 2(l+b)h +(l*b).

Vaishnavi said:   1 decade ago
@malar

2(l+b) is only the perimeter of the rectangle (2D) with only length and breadth and no thickness / depth.

Here it is the wall of the tank with depth of 6 m.

Hope you got the idea.

Abc said:   1 decade ago
How you know the bottom is rectangular or may be any other?

Siva said:   1 decade ago
What is the formula if it is a room and need to plaster four walls, bottom and top as well ?


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