Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Answer: Option
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
 Required number of tiles = |
 |
1517 x 902 |  |
= 814. |
| 41 x 41 |
Discussion:
56 comments Page 6 of 6.
Sakshi said:
8 years ago
Thank you @Srivalli.
Harish said:
7 years ago
Here 41 * 37=1517 and 41 * 22=902.
So, 41 comes in both the no. (which is called hcf).
Now the area of the floor is 1512 * 902.
So least no. of tiles to cover the floor = n * 41^2 (as square tile can be taken of length 41).
Therefore n =37*22 =814.
So, 41 comes in both the no. (which is called hcf).
Now the area of the floor is 1512 * 902.
So least no. of tiles to cover the floor = n * 41^2 (as square tile can be taken of length 41).
Therefore n =37*22 =814.
(2)
Richy said:
7 years ago
@All.
If we want to get the least number of tiles, the largest tiles must be used. This is why hcf is used. If you want to get the most number of tiles, then, the smallest tiles will be used, which is lcm.
If we want to get the least number of tiles, the largest tiles must be used. This is why hcf is used. If you want to get the most number of tiles, then, the smallest tiles will be used, which is lcm.
(8)
Shekarreddy said:
7 years ago
Why we use HCF here?
(1)
Raghuvansh said:
6 years ago
Thanks for your explanation of HCF @Ibrahimsha.
(1)
Sudarshan jain said:
6 years ago
Thanks all.
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