Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Answer: Option
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
 Required number of tiles = |
 |
1517 x 902 |  |
= 814. |
| 41 x 41 |
Discussion:
56 comments Page 5 of 6.
Koushik kallamadi said:
1 decade ago
Hi friends,
We can also use the dimensions (9.02*9.02) + (6.15*6.15) +2(2.87*2.87) +7(0.41*0.41) and totally 11 square tiles of different lengths.
We can also use the dimensions (9.02*9.02) + (6.15*6.15) +2(2.87*2.87) +7(0.41*0.41) and totally 11 square tiles of different lengths.
Suparna said:
1 decade ago
Is there any other easy method to calculate HCF?
Pradeep said:
1 decade ago
The highest no that can divide both length and breadth so that the tiles used can occupy all the available space exactly.
Sumi said:
1 decade ago
@Shashi. Well said.
To calculate least no.of square we need largest tiles. That means we need to have highest common factor for 1517 & 902.
To calculate least no.of square we need largest tiles. That means we need to have highest common factor for 1517 & 902.
Shashi said:
1 decade ago
To calculate least no.of square we need largest tiles so that it can cover it in less no of tiles so we need a highest number out of (1517 & 902) which can divide the area entirely and it can only be obtained by HCF.
Hardik said:
1 decade ago
Please explain all steps.
Vani varma said:
1 decade ago
Thank you shanthi, shasank and Ibrahimsha.
Balajisingh said:
1 decade ago
Imbrhimsha now I'm clear with HCF thank you.
Sara said:
1 decade ago
Why we require hcf here?
Ibrahimsha said:
1 decade ago
902)1517(1
902
------
615)902(1
615
---
287)615(2
574
---
41)287(7
287
---
0
By this method of successful division, remainder goes 0. Last divisor forms your req. HCF....
So 41 is ur HCF :-)
902
------
615)902(1
615
---
287)615(2
574
---
41)287(7
287
---
0
By this method of successful division, remainder goes 0. Last divisor forms your req. HCF....
So 41 is ur HCF :-)
(3)
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