Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 10)
10.
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
814
820
840
844
Answer: Option
Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) cm2.

Required number of tiles = 1517 x 902 = 814.
41 x 41

Discussion:
56 comments Page 3 of 6.

Shridhar said:   9 years ago
Thank you for your solution @Ibrahimsha.

Sathyaraj k said:   9 years ago
Thank you @Ibrahimsha.

Abhi said:   9 years ago
Please tell me how many tiles will be used in that room whose length or breath is 20 m and 16 cm or 15 m 60 cm.

Ramesh said:   9 years ago
I didn't understand the Last step multiplication. Someone help me.

Pink_love said:   9 years ago
@Jhanvi.

In the question, one length is given in cm and another in m. So we have to convert m into cm.
i.e 15m=15 * 100cm (same for the breadth).

And for HCF.

1517 = 37 * 41,
902 = 22 * 41,

So HCF = 41,
Area = 41 * 41,
Req no of tiles = 1517 * 902/41 * 41 = 814.

Anoop said:   9 years ago
@Suresh.

Thank you for explaining why HCF is used here..

Jhanvi said:   9 years ago
How you got 1517 and 902? Please explain.
(1)

ABDULLAH AKHTAR said:   9 years ago
@Narayanan.

Thanks for explaining it.

Narayanan said:   9 years ago
The least number is asked that means a single tile with the maximum dimension.

For this try LCM , you will get the maximum number of tiles with minimum dimensions whereas, in HCF, you will get the largest dimension possible. So that only HCF is used to find the answer.

Bhavna said:   10 years ago
We are converting metres to centimetres.


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