Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 4 of 8.
Lekshmi said:
1 decade ago
Same doubt as sai said above,
60x + 40x - x2 = 291?
60x+40x?
60x + 40x - x2 = 291?
60x+40x?
Rkbm said:
1 decade ago
X be the width. (60-x) (40-x) is area of remaining field.
Sekhar said:
7 years ago
60x+40x-291 = x*x.
Then what about 291?
Can you explain?
Then what about 291?
Can you explain?
(2)
Aaru said:
1 decade ago
Ayoosh your explaination is nice. I understood well now,
Abhi said:
1 decade ago
Ayoosh explaination really helped me. Thanks Ayoosh :)
Vijay said:
7 years ago
@Ankanna.
Your explanation really helped me. Thanks.
Your explanation really helped me. Thanks.
Manogaram said:
1 decade ago
Hats off to ayoosh and prajwal for nice explanation.
Himanshu said:
7 years ago
Why only square of width is taken and not length?
(1)
Sly said:
7 years ago
Thanks all for explaining the answer in detail.
(1)
Pratiti Das said:
9 years ago
How come two concentric roads have 60x + 40x?
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