Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 3 of 8.
Swastik said:
6 years ago
Use formula,
X+Y+(X*Y/100) for an increase in length and breadth of any quadrilateral.
Which is,
=20+20+(20*20/100)
=20+20+4
=44%.
X+Y+(X*Y/100) for an increase in length and breadth of any quadrilateral.
Which is,
=20+20+(20*20/100)
=20+20+4
=44%.
(1)
Tanya said:
1 decade ago
Its because the area of 2 roads has come out to be 291m2. Rest of the explaination has been given by prajwal.
Imran Shaikh said:
1 decade ago
How is this calculated ?
x2 - 100x + 291 = 0 ----------> (x - 97)(x - 3) = 0
x2 - 100x + 291 = 0 ----------> (x - 97)(x - 3) = 0
Theodore said:
8 years ago
What will be the LENGTH of the road? Can Anyone help me to find out the answer?
Naju said:
1 decade ago
Draw the figure you can c two cross road intersect, so we need to subtract it.
VAN said:
8 years ago
So, x is squared because it is assumed that the two x's are of equal value?
MAHI said:
1 decade ago
40*3=120
60*3=180
TOTAL=300
LESS=291
BALANCE=9 SQCM
THAT IS 3*3
ANS=3.
60*3=180
TOTAL=300
LESS=291
BALANCE=9 SQCM
THAT IS 3*3
ANS=3.
Saila said:
10 years ago
@Puskar,
You may go through Diego's answer for better understanding.
You may go through Diego's answer for better understanding.
Puskar prasun said:
10 years ago
Guys! it should be 2x^2 instead of simply x^2? don't you all agree?
Hashmuddin said:
1 decade ago
x2 -100x +291=0
x2 -97x -3x +291=0
x(x -97)-3(x-97)=0
(x-97)(x-3)=0
x2 -97x -3x +291=0
x(x -97)-3(x-97)=0
(x-97)(x-3)=0
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