Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 5)
5.
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answer: Option
Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Video Explanation: https://youtu.be/R3CtrAKGxkc
Discussion:
75 comments Page 5 of 8.
Sai said:
1 decade ago
What is the need of 60x + 40X -pow (x, 2) ?
Sujay ramesh said:
1 decade ago
Thanks ayoosh. Your explanation is good :).
Shivangi goel said:
7 years ago
How this quadratic equation is formed in x?
Torikul said:
8 years ago
Thanks for your good explanation @Priyanka.
Salman said:
8 years ago
Thanks to all for giving the explanation.
Koushik said:
1 decade ago
Excellent Ayoosh. Thank you very much.
Praveen said:
1 decade ago
Thanks ayoosh very nice explanation.
Ganesh Kumar said:
2 years ago
Why - x^2? can anyone explain this?
(5)
Aayushi said:
9 years ago
Where is 291?
How to solve this?
How to solve this?
Savita said:
9 years ago
Thanks @Priyanka for the answer.
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