Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 4)
4.
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
40%
42%
44%
46%
Answer: Option
Explanation:

Let original length = x metres and original breadth = y metres.

Original area = (xy) m2.

New length = 120 x m = 6 x m.
100 5

New breadth = 120 y m = 6 y m.
100 5

New Area = 6 x x 6 y m2 = 36 xy m2.
5 5 25

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy - xy

= xy(36/25 - 1)

= xy(11/25) or (11/25)xy

Increase % = 11 xy x 1 x 100 % = 44%.
25 xy

Video Explanation: https://youtu.be/I3jLjLPn1W4

Discussion:
74 comments Page 8 of 8.

Kadhal said:   4 years ago
@All.

My Question is How they assume both l and b equal to 100, in rectangle l and b they never in equal size, right?
(10)

Omveer said:   3 years ago
Square Is also a Rectangle.

Assume both sides to be 100.
Actual Area = 10000.
With 20% increase in each side Area = 102*102=14400,Diffrence = 4400.
% Increase in Area = 4400/10000 * 100 = 44%.
(13)

Akil said:   3 years ago
It is simple.

(1.2) L* (1.2) B = 1. 44 (L*B).

So, the total area increase is 44%.
(18)

N G GANESH said:   3 weeks ago
In simple way:

Let's take;
Length l = 10.
Breadth b = 10.
=> l × b = 100
20% increase in side length means 20% of 10 is 2.
L = 12.
B = 12.
L×b = 12 × 12 = 144, which means 44% increase in area.
(3)


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