Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 4)
4.
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
40%
42%
44%
46%
Answer: Option
Explanation:

Let original length = x metres and original breadth = y metres.

Original area = (xy) m2.

New length = 120 x m = 6 x m.
100 5

New breadth = 120 y m = 6 y m.
100 5

New Area = 6 x x 6 y m2 = 36 xy m2.
5 5 25

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy - xy

= xy(36/25 - 1)

= xy(11/25) or (11/25)xy

Increase % = 11 xy x 1 x 100 % = 44%.
25 xy

Video Explanation: https://youtu.be/I3jLjLPn1W4

Discussion:
74 comments Page 7 of 8.

Sarvesh agarwal said:   8 years ago
A = L*B.
A = (1+1/5)(1+1/5).
A = 36/25LB.
A = 144%.
i.e 44%.

Kumar Gowda said:   6 years ago
= 20+20(20*20/100).
= 40+(400/100),
= 40+(4),
= 40+4,
= 44%.
(5)

Kumar said:   10 years ago
I can't understand your answer. Please explain brief.

Mani said:   1 decade ago
From where have we got new length and new breadth.

Vasavi said:   9 years ago
@Bhupendra.

How did you get the new side as 6x/5?

Ajay said:   9 years ago
Shortcut :

20 + 20 + ((20 * 20)/100) = 44.

Hussain said:   8 years ago
a*(200+a)/100.
so, 20*(200+20)/100.
=44%.

Bubai mitra said:   9 years ago
If let it 100. It will make more easy.

Krishna said:   1 decade ago
Bhupendra has solved this correctly !

Gokul said:   9 years ago
Explained well @Shashank.


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