Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 4)
4.
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
Answer: Option
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = (xy) m2.
New length = | ![]() |
120 | x | ![]() |
= | ![]() |
6 | x | ![]() |
100 | 5 |
New breadth = | ![]() |
120 | y | ![]() |
= | ![]() |
6 | y | ![]() |
100 | 5 |
New Area = | ![]() |
6 | x x | 6 | y | ![]() |
= | ![]() |
36 | xy | ![]() |
5 | 5 | 25 |
The difference between the original area = xy and new-area 36/25 xy is
= (36/25)xy - xy
= xy(36/25 - 1)
= xy(11/25) or (11/25)xy
![]() |
![]() |
11 | xy x | 1 | x 100 | ![]() |
= 44%. |
25 | xy |
Video Explanation: https://youtu.be/I3jLjLPn1W4
Discussion:
74 comments Page 7 of 8.
Sarvesh agarwal said:
8 years ago
A = L*B.
A = (1+1/5)(1+1/5).
A = 36/25LB.
A = 144%.
i.e 44%.
A = (1+1/5)(1+1/5).
A = 36/25LB.
A = 144%.
i.e 44%.
Kumar Gowda said:
6 years ago
= 20+20(20*20/100).
= 40+(400/100),
= 40+(4),
= 40+4,
= 44%.
= 40+(400/100),
= 40+(4),
= 40+4,
= 44%.
(5)
Kumar said:
10 years ago
I can't understand your answer. Please explain brief.
Mani said:
1 decade ago
From where have we got new length and new breadth.
Vasavi said:
9 years ago
@Bhupendra.
How did you get the new side as 6x/5?
How did you get the new side as 6x/5?
Ajay said:
9 years ago
Shortcut :
20 + 20 + ((20 * 20)/100) = 44.
20 + 20 + ((20 * 20)/100) = 44.
Hussain said:
8 years ago
a*(200+a)/100.
so, 20*(200+20)/100.
=44%.
so, 20*(200+20)/100.
=44%.
Bubai mitra said:
9 years ago
If let it 100. It will make more easy.
Krishna said:
1 decade ago
Bhupendra has solved this correctly !
Gokul said:
9 years ago
Explained well @Shashank.
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