Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 4)
4.
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
40%
42%
44%
46%
Answer: Option
Explanation:

Let original length = x metres and original breadth = y metres.

Original area = (xy) m2.

New length = 120 x m = 6 x m.
100 5

New breadth = 120 y m = 6 y m.
100 5

New Area = 6 x x 6 y m2 = 36 xy m2.
5 5 25

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy - xy

= xy(36/25 - 1)

= xy(11/25) or (11/25)xy

Increase % = 11 xy x 1 x 100 % = 44%.
25 xy

Video Explanation: https://youtu.be/I3jLjLPn1W4

Discussion:
74 comments Page 6 of 8.

Hanny Gupta said:   1 decade ago
A1 = 100*100 = 10000.

A2 = 120*120 = 14400.

A2-A1 = 14400-10000 = 4400.

(A2-A1)% = 44 %.

Lork said:   10 years ago
Old a b ==> ab.

New 1.2 a 1.2 b ==> 1.44 ab.

Increase = 1.44 ab - ab = 0.44 = 44%.

Ajit said:   9 years ago
Assume that total area is 100.

20% of 100 = 120.

20% of 120 = 144.

144 - 100 = 44.

Akil said:   3 years ago
It is simple.

(1.2) L* (1.2) B = 1. 44 (L*B).

So, the total area increase is 44%.
(18)

Sdasdasdad said:   1 decade ago
a=l*b=120l*120b.

a=14400lb.

a=100l*100b.

a=10000lb.

%=44/100.

44% answer.

Madhu said:   8 years ago
Increases 20% so (120/100) * (120/100) =14400/10000=144%.

44% increases.

MAHESHKRISHNAN D said:   7 years ago
100*100 = 10000(1)
120*120 = 14400(2)
1-2 = 4400/100.
= 44%.
(3)

Subbu said:   5 years ago
Can anyone show how it can be solved by using derivatives? please.
(1)

Hema said:   1 decade ago
Why here you take length = (120/100)x and breadth = (120/100)y?

Harmanpreet said:   7 years ago
Each side 20% increased thus 120*120/100=144,
then 144-100 =44.


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