Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 4)
4.
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
Answer: Option
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = (xy) m2.
New length = | ![]() |
120 | x | ![]() |
= | ![]() |
6 | x | ![]() |
100 | 5 |
New breadth = | ![]() |
120 | y | ![]() |
= | ![]() |
6 | y | ![]() |
100 | 5 |
New Area = | ![]() |
6 | x x | 6 | y | ![]() |
= | ![]() |
36 | xy | ![]() |
5 | 5 | 25 |
The difference between the original area = xy and new-area 36/25 xy is
= (36/25)xy - xy
= xy(36/25 - 1)
= xy(11/25) or (11/25)xy
![]() |
![]() |
11 | xy x | 1 | x 100 | ![]() |
= 44%. |
25 | xy |
Video Explanation: https://youtu.be/I3jLjLPn1W4
Discussion:
74 comments Page 4 of 8.
Ravi said:
9 years ago
The rational number with recurring decimal expansion 0.12 is __________.
Can anyone answer the question?
Can anyone answer the question?
Bhaskar Chandra said:
9 years ago
Trick:
If increase in length of breadth & width is x% then the increase in area a' = 2x + (square x)/100.
Quick method: if x=20% then a'.
20 * 2 + (20 * 20 = 4.00) = 44.00.
If x = 4 then a' = 4 * 2 + 0.(4 * 4) = 8 + 0.16 = 8.16%
If x = 5 then a' = 5 * 2 + 0.(5 * 5) = 10 + 0.25 = 10.25.
If x = 6 then a' = 6 * 2 + 0.(6 * 6) = 12 + 0.36 = 12.36.
If x = 7 then a' = 7 * 2 + 0.(7 * 7) = 14 + 0.49 = 14.49.
If x = 8 then a' = 8 * 2 + 0.(8 * 8) = 16 + 0.64 = 16.64.
If x = 9 then a' = 9 * 2 + 0.(9 * 9) = 18 + 0.81 = 18.81.
If x = 10 then a' = 10 * 2 + 0.(10 * 10) = 20 + 1.00 = 21.
If x = 11 then a' = 11 * 2 + 0.(11 * 11) = 22 + 1.21 = 23.21.
Note : When the product is a number of more than three decimals, place a decimal point after two places from the right.
If increase in length of breadth & width is x% then the increase in area a' = 2x + (square x)/100.
Quick method: if x=20% then a'.
20 * 2 + (20 * 20 = 4.00) = 44.00.
If x = 4 then a' = 4 * 2 + 0.(4 * 4) = 8 + 0.16 = 8.16%
If x = 5 then a' = 5 * 2 + 0.(5 * 5) = 10 + 0.25 = 10.25.
If x = 6 then a' = 6 * 2 + 0.(6 * 6) = 12 + 0.36 = 12.36.
If x = 7 then a' = 7 * 2 + 0.(7 * 7) = 14 + 0.49 = 14.49.
If x = 8 then a' = 8 * 2 + 0.(8 * 8) = 16 + 0.64 = 16.64.
If x = 9 then a' = 9 * 2 + 0.(9 * 9) = 18 + 0.81 = 18.81.
If x = 10 then a' = 10 * 2 + 0.(10 * 10) = 20 + 1.00 = 21.
If x = 11 then a' = 11 * 2 + 0.(11 * 11) = 22 + 1.21 = 23.21.
Note : When the product is a number of more than three decimals, place a decimal point after two places from the right.
Naveed Subhan said:
9 years ago
What if you don't know what the percentage of increase or decrease is and what if one side is increasing and the other is decreasing?
Let a = percentage change(increase or decrease)on one side and b= percentage change of other side then:
If both sides as are increasing = (a + b) + ab/100.
If both sides are decreasing = (a + b) - ab/100.
If one side is increasing (positive, say a) and one side is decreasing (negative, say b) = a - b - ab/100.
Let a = percentage change(increase or decrease)on one side and b= percentage change of other side then:
If both sides as are increasing = (a + b) + ab/100.
If both sides are decreasing = (a + b) - ab/100.
If one side is increasing (positive, say a) and one side is decreasing (negative, say b) = a - b - ab/100.
Kasaiah said:
9 years ago
Why all of them taking a length as 100 that and is not a square. Why don't you try it length and breadth with separate values like 100 & 200?
Ramesh said:
9 years ago
Let original length and breadth be 100.
So new length and breadth are 120
New Area = 120 * 120 so 14400.
Old area = 100 * 100 = 10000.
So diff = 4400.
Error = 4400/(100 * 100) * 100.
So, 44%.
So new length and breadth are 120
New Area = 120 * 120 so 14400.
Old area = 100 * 100 = 10000.
So diff = 4400.
Error = 4400/(100 * 100) * 100.
So, 44%.
Ajit said:
9 years ago
Assume that total area is 100.
20% of 100 = 120.
20% of 120 = 144.
144 - 100 = 44.
20% of 100 = 120.
20% of 120 = 144.
144 - 100 = 44.
Shailesh said:
9 years ago
Make it simple yar! Parentage increase increase of rectangle or square will be same.
Assume 10 x 10 original square Area will be 100 simple.
Now increase side length by 20 % will make 12 x 12 square Area will be 144.
So simple should I tell you the correct answer (C) 44.
Assume 10 x 10 original square Area will be 100 simple.
Now increase side length by 20 % will make 12 x 12 square Area will be 144.
So simple should I tell you the correct answer (C) 44.
NAVEEN said:
9 years ago
Given sides of rectangle are increased by 20%.
Let us take length L = 20.
Breadth B = 10.
Area of rectangle = LxB = 10x20 = 200.
After 20% increase L = 24.
B = 12.
Area of rectangle = LxB = 24x12 = 288.
Area increased to 288 from 200 = 44%.
Same for square.
Let us take length L = 20.
Breadth B = 10.
Area of rectangle = LxB = 10x20 = 200.
After 20% increase L = 24.
B = 12.
Area of rectangle = LxB = 24x12 = 288.
Area increased to 288 from 200 = 44%.
Same for square.
Kumar said:
10 years ago
I can't understand your answer. Please explain brief.
Lork said:
10 years ago
Old a b ==> ab.
New 1.2 a 1.2 b ==> 1.44 ab.
Increase = 1.44 ab - ab = 0.44 = 44%.
New 1.2 a 1.2 b ==> 1.44 ab.
Increase = 1.44 ab - ab = 0.44 = 44%.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers