Aptitude - Area - Discussion

Discussion Forum : Area - General Questions (Q.No. 4)
4.
The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
40%
42%
44%
46%
Answer: Option
Explanation:

Let original length = x metres and original breadth = y metres.

Original area = (xy) m2.

New length = 120 x m = 6 x m.
100 5

New breadth = 120 y m = 6 y m.
100 5

New Area = 6 x x 6 y m2 = 36 xy m2.
5 5 25

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy - xy

= xy(36/25 - 1)

= xy(11/25) or (11/25)xy

Increase % = 11 xy x 1 x 100 % = 44%.
25 xy

Video Explanation: https://youtu.be/I3jLjLPn1W4

Discussion:
74 comments Page 4 of 8.

Ravi said:   9 years ago
The rational number with recurring decimal expansion 0.12 is __________.

Can anyone answer the question?

Bhaskar Chandra said:   9 years ago
Trick:
If increase in length of breadth & width is x% then the increase in area a' = 2x + (square x)/100.

Quick method: if x=20% then a'.

20 * 2 + (20 * 20 = 4.00) = 44.00.

If x = 4 then a' = 4 * 2 + 0.(4 * 4) = 8 + 0.16 = 8.16%
If x = 5 then a' = 5 * 2 + 0.(5 * 5) = 10 + 0.25 = 10.25.
If x = 6 then a' = 6 * 2 + 0.(6 * 6) = 12 + 0.36 = 12.36.
If x = 7 then a' = 7 * 2 + 0.(7 * 7) = 14 + 0.49 = 14.49.
If x = 8 then a' = 8 * 2 + 0.(8 * 8) = 16 + 0.64 = 16.64.
If x = 9 then a' = 9 * 2 + 0.(9 * 9) = 18 + 0.81 = 18.81.
If x = 10 then a' = 10 * 2 + 0.(10 * 10) = 20 + 1.00 = 21.
If x = 11 then a' = 11 * 2 + 0.(11 * 11) = 22 + 1.21 = 23.21.

Note : When the product is a number of more than three decimals, place a decimal point after two places from the right.

Naveed Subhan said:   9 years ago
What if you don't know what the percentage of increase or decrease is and what if one side is increasing and the other is decreasing?

Let a = percentage change(increase or decrease)on one side and b= percentage change of other side then:
If both sides as are increasing = (a + b) + ab/100.
If both sides are decreasing = (a + b) - ab/100.
If one side is increasing (positive, say a) and one side is decreasing (negative, say b) = a - b - ab/100.

Kasaiah said:   9 years ago
Why all of them taking a length as 100 that and is not a square. Why don't you try it length and breadth with separate values like 100 & 200?

Ramesh said:   9 years ago
Let original length and breadth be 100.
So new length and breadth are 120
New Area = 120 * 120 so 14400.
Old area = 100 * 100 = 10000.
So diff = 4400.
Error = 4400/(100 * 100) * 100.
So, 44%.

Ajit said:   9 years ago
Assume that total area is 100.

20% of 100 = 120.

20% of 120 = 144.

144 - 100 = 44.

Shailesh said:   9 years ago
Make it simple yar! Parentage increase increase of rectangle or square will be same.

Assume 10 x 10 original square Area will be 100 simple.

Now increase side length by 20 % will make 12 x 12 square Area will be 144.

So simple should I tell you the correct answer (C) 44.

NAVEEN said:   9 years ago
Given sides of rectangle are increased by 20%.

Let us take length L = 20.

Breadth B = 10.

Area of rectangle = LxB = 10x20 = 200.

After 20% increase L = 24.

B = 12.

Area of rectangle = LxB = 24x12 = 288.

Area increased to 288 from 200 = 44%.

Same for square.

Kumar said:   10 years ago
I can't understand your answer. Please explain brief.

Lork said:   10 years ago
Old a b ==> ab.

New 1.2 a 1.2 b ==> 1.44 ab.

Increase = 1.44 ab - ab = 0.44 = 44%.


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