Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 13)
13.
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Answer: Option
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = | ![]() |
5300 | ![]() |
m = 200 m. |
26.50 |
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Discussion:
14 comments Page 2 of 2.
Rubel Hossen said:
7 years ago
Let, Length = x, then breadth = x-20,
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40)*26.50 = 5300,
106x-1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40)*26.50 = 5300,
106x-1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
Soundarya said:
6 years ago
Why we are using perimeter, here? Please explain me.
Geetha said:
5 years ago
I can't understand this problem please someone explain.
SUBA said:
5 years ago
Why should we take perimeter here?
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