Aptitude - Area - Discussion
Discussion Forum : Area - General Questions (Q.No. 13)
13.
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Answer: Option
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = | ![]() |
5300 | ![]() |
m = 200 m. |
26.50 |
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Discussion:
14 comments Page 2 of 2.
Saumya said:
6 years ago
For those who are asking why perimeter.
As the question mentions fencing, and for fencing outer boundary is calculated i.e. perimeter.
As the question mentions fencing, and for fencing outer boundary is calculated i.e. perimeter.
(1)
Geetha said:
5 years ago
I can't understand this problem please someone explain.
SUBA said:
5 years ago
Why should we take perimeter here?
Suman said:
3 years ago
Let, Length = x, then breadth = x-20,
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40) * 26.50 = 5300,
106x - 1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
So, Perimeter = 2(x+x-20) = 2(2x-20) = 4x-40,
ATQ,
(4x-40) * 26.50 = 5300,
106x - 1060 = 5300,
106x = 5300+1060,
106x = 6360,
x = 6360/106,
x = 60.
(3)
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