Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
1
3
1
4
1
5
1
7
Answer: Option
Explanation:

Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water.

Quantity of water in new mixture = 3 - 3x + x litres
8

Quantity of syrup in new mixture = 5 - 5x litres
8

3 - 3x + x = 5 - 5x
8 8

5x + 24 = 40 - 5x

10x = 16

x = 8 .
5

So, part of the mixture replaced = 8 x 1 = 1 .
5 8 5

Discussion:
203 comments Page 8 of 21.

Kabalai khan said:   8 years ago
3:5 is the ratio given take the largest number in it which is 5.
as per question half of milk and syrup so, 5:5 in large number.
See the difference which is 2 of the taken ratio is 10 so answer is 1/5.

Nandu said:   8 years ago
Water : 3 Syrup : 5 & mix = half water & half syrup.
3:5.

[(Diff between 3 & 5)
1:1 *5,
5:5,
2/10= 1/5.

(2= diff between 3 & 5)
(10= 5+5).

I Hope this is the easy method.

Sadik shaik said:   1 decade ago
To make equal parts, we just take 1 part from syrup and replace with water to get 4 parts of water and 4 parts of syrup.

So we are replacing 1 part of syrup of 5 parts with water, so the answer is 1/5.

Fazle Rasool said:   9 years ago
Given : w:s=3:5,
After removal of x litter the ratio becomes w:s=1:1,

Quantity of water before and after is,
3/8 - 3x/8 +x = 1/2.
5x/8 = 1/8.

x = 1/5 this is the answer and it is a simple method.

Radheshyam said:   1 decade ago
Let volume is 8.

Water = 3/8 syrup = 5/8.

According to question,

Suppose y mixture(water,syrup)are drawn.

Water quantity is 3y/8 and syrup quantity is 5y/8.

3/8-3y/8+y = 5/8-5y/8.

y = 1/5.
(1)

Rajnish jha said:   1 decade ago
New quantity of syrup = 5x - 5y.
New quantity of water = 3x - 3y + 8y = 3x + 5y.
They are equal to each other.
=> 5x - 5y = 3x + 5y.
=> 2x = 10y.
=> y/x = 2/10 = 1/5.
=> 8y/8x = 1/5.

Sybil said:   1 decade ago
A solution of sugar syrup has 15% sugar. Another solution has 5% sugar. How many litres of the second solution must be added to 20% litres of the first solution to make a solution of 10% sugar?
(1)

Haniffa said:   1 decade ago
WATER : SYRUP

3 : 5 = 8.
2 : 0 = 2 (TO BOTH BECOME EQUAL ADD 2 UNITS TO WATER).
5 : 5 = 10 (RATIO IS EQUAL NOW).

SO, ADDED AMOUNT OF WATER IS 2/10 OF FULL AMOUNT. IF YOU SIMPLIFIED IT'S 1/5.

Krishjlk@gmail.com said:   2 decades ago
Your great surender. Thanks a lot. Really that is very good explanation.

Instead of remembering the formulas you came with the theory.

And concept. Good excellent. Thank you for your post.

Shivangi said:   6 years ago
Final(syrup)=initial(syrup)*(1-(qt_replaced/total_mix).
X is a mixture replaced with water.
p is the total quantity of mixture.

4/8=5/8(1-x/p).

We need to find x/p which is 1/5 i.e answer.


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