Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 1)
1.
A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: Option
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = | ![]() |
3 - | 3x | + x | ![]() |
litres |
8 |
Quantity of syrup in new mixture = | ![]() |
5 - | 5x | ![]() |
litres |
8 |
![]() |
![]() |
3 - | 3x | + x | ![]() |
= | ![]() |
5 - | 5x | ![]() |
8 | 8 |
5x + 24 = 40 - 5x
10x = 16
![]() |
8 | . |
5 |
So, part of the mixture replaced = | ![]() |
8 | x | 1 | ![]() |
= | 1 | . |
5 | 8 | 5 |
Discussion:
198 comments Page 8 of 20.
Iptisam said:
8 years ago
1/2(y-x)/y.
=1/2(5-3)/5,
= 1/2 * 2/5,
= 1/5.
=1/2(5-3)/5,
= 1/2 * 2/5,
= 1/5.
Vikas said:
8 years ago
How did you get that equation 5x+24=40-5x?
Shriyash sharma said:
8 years ago
Formula.
Final volume or the ratio of solute A=initial volume or ratio solution A(1-solute to be replaced/total volume)^n.
let A=syrup, B=water.
Putting in formula:
assuming volume is 1litre.
A=5/8, B=3/8.
applying formula on solute A because it will be reduced after an operation.
so,
4/8=5/8(1-x/1),
x=1/5.
Final volume or the ratio of solute A=initial volume or ratio solution A(1-solute to be replaced/total volume)^n.
let A=syrup, B=water.
Putting in formula:
assuming volume is 1litre.
A=5/8, B=3/8.
applying formula on solute A because it will be reduced after an operation.
so,
4/8=5/8(1-x/1),
x=1/5.
Murali D said:
8 years ago
Very good explanation, Thanks @Surendrareddy.
Dileep said:
8 years ago
Let us consider the mixture to be of 8 litres (3 Litres of water + 5 litres of Syrup).
Amount of Water in the 8 litre Mixture : 3/8.
Amount of Syrup in the 8 litre Mixture : 5/8.
For easy calculation, I am considering the mixture to be of 10 litres.
Hence Amount of Water in the 10 litre Mixture : 3/8 * 10 = 3.75.
Amount of Syrup in the 10 litre Mixture : 5/8 * 10 = 6.25.
We need to replace 1.25 litres of syrup from the mixture and replace with water 50 make it 5 / 5. Hence we need to replace 2 litres of mixture (.625+.375) * 2.
2 Litres out of 10 litres is 20% or 1/5.
Amount of Water in the 8 litre Mixture : 3/8.
Amount of Syrup in the 8 litre Mixture : 5/8.
For easy calculation, I am considering the mixture to be of 10 litres.
Hence Amount of Water in the 10 litre Mixture : 3/8 * 10 = 3.75.
Amount of Syrup in the 10 litre Mixture : 5/8 * 10 = 6.25.
We need to replace 1.25 litres of syrup from the mixture and replace with water 50 make it 5 / 5. Hence we need to replace 2 litres of mixture (.625+.375) * 2.
2 Litres out of 10 litres is 20% or 1/5.
Shanmukha said:
8 years ago
Thanks for your active cooperation. It's very helpful.
Jas said:
8 years ago
A 10 litre container holds a mixture of water and sugar, the volume of sugar being 15% of total volume. A few litres of the mixture is released and an equal amount of water is added. Then the same amount of the mixture as before is released and replaced with water for a second time. As a result, the sugar content becomes 10% of total volume. What is the approximate quantity of mixture released each time? please solve this sum?
Can anyone solve this?
Can anyone solve this?
ABHIJIT said:
9 years ago
w:s
3:5
Consider in tens
30 : 50
3 : 5
1:1
40:40
To get 40 syrup you need to remove 10.
as the ratio is 3:5.
So, to remove 10 you need to remove 8x2=16 volume of liquid = 16/80 = 1/5.
3:5
Consider in tens
30 : 50
3 : 5
1:1
40:40
To get 40 syrup you need to remove 10.
as the ratio is 3:5.
So, to remove 10 you need to remove 8x2=16 volume of liquid = 16/80 = 1/5.
Manisha said:
9 years ago
Let's consider total mix is100 litre, Water = 3parts = 37.5liter.
Syrup = 5parts = 62.5 litre.
We have to draw liquid so that syrup remains.
50 litre for that we have to draw out the quantity of mixture which contains 12.5 litres of syrup.
Now mixture containing 12.5-litre syrup contain = 12.5 * 8/5 = 20 litre.
We have to draw out 20litre mix.
i.e 20/100 = 1/5 mix have to replace for getting 1:1 mixture.
Syrup = 5parts = 62.5 litre.
We have to draw liquid so that syrup remains.
50 litre for that we have to draw out the quantity of mixture which contains 12.5 litres of syrup.
Now mixture containing 12.5-litre syrup contain = 12.5 * 8/5 = 20 litre.
We have to draw out 20litre mix.
i.e 20/100 = 1/5 mix have to replace for getting 1:1 mixture.
Rushit said:
9 years ago
Thank you for teaching the new method friends!
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