Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 10)
10.
In what ratio must water be mixed with milk to gain 16
% on selling the mixture at cost price?

Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1.
S.P. of 1 litre of mixture = Re.1, Gain = | 50 | %. |
3 |
![]() |
![]() |
100 x | 3 | x 1 | ![]() |
= | 6 |
350 | 7 |
By the rule of alligation, we have:
C.P. of 1 litre of water C.P. of 1 litre of milk | |||||
0 | Mean Price
| Re. 1 | |||
|
|
![]() |
1 | : | 6 | = 1 : 6. |
7 | 7 |
Discussion:
51 comments Page 4 of 6.
Amit said:
1 decade ago
Yes @Supritha you are right.
How can we take lower C.P water at right side in problem no. 6?
How can we take lower C.P water at right side in problem no. 6?
Supritha K.S. said:
1 decade ago
Why is C.P. of 1 liter of milk taken on the left hand side as per the rule of alligation in this problem. Unlike C.P. of 1 liter of milk which is taken on the right hand side in 6th sum and other sums?
Shivani said:
1 decade ago
How we get to know either they are asking milk to water ratio or water to milk ratio that's why it can be 6:1 and 1:6?
Floretamit said:
1 decade ago
Let total quantity was x and cost price of milk was 100.
Since we have to sell milk with same price but have to gain profit 50/3% of 100 rupee so here selling price will be 100 and cost price of mixture.
== Selling price - Profit.
==100-50/3 = 250/3.
Now, use allegation by x liter milk o milk that is water.
100.
250/3.
250 : 50.
= 5 : 1.
Now the quantity of water that should mixed with milk will be.
1/6*x that is water must be mixed 1/6th weight of milk weight. That means if initial milk was kg kg than 1 liter water must be mixed to get 50/3 % profit by selling on original cost price.
Since we have to sell milk with same price but have to gain profit 50/3% of 100 rupee so here selling price will be 100 and cost price of mixture.
== Selling price - Profit.
==100-50/3 = 250/3.
Now, use allegation by x liter milk o milk that is water.
100.
250/3.
250 : 50.
= 5 : 1.
Now the quantity of water that should mixed with milk will be.
1/6*x that is water must be mixed 1/6th weight of milk weight. That means if initial milk was kg kg than 1 liter water must be mixed to get 50/3 % profit by selling on original cost price.
Oken said:
1 decade ago
Let C.P. of 1 litre of milk be Re 1.
Then S.P. of the mixture is also Re 1.
C.P. of 1 titre of the mixture = 1-50/300 = 250/300 = 5/6.
As per my opinion C.P. of 1 litre of the mixture is Rs. 5/6 but everyone told me it should be 6/7.
How is it so? Anybody please help.
Then S.P. of the mixture is also Re 1.
C.P. of 1 titre of the mixture = 1-50/300 = 250/300 = 5/6.
As per my opinion C.P. of 1 litre of the mixture is Rs. 5/6 but everyone told me it should be 6/7.
How is it so? Anybody please help.
Alagu said:
1 decade ago
How the C.P of 1 liter milk is Re. 1?
Sowmya said:
1 decade ago
Blindly assumed like this type problems.
16 2/35% = 50/3%.
So, 50/3/100 = 50/3*1/100 = 50/300 = 1/6.
So, 1:6.
16 2/35% = 50/3%.
So, 50/3/100 = 50/3*1/100 = 50/300 = 1/6.
So, 1:6.
Manan said:
1 decade ago
@Yuvraj : (16*3+2)/3 = (48+2)/3 = 50/3.
Thats how a mixed fraction is solved.
Thats how a mixed fraction is solved.
Pooja said:
1 decade ago
Can anyone say why we are taking as 3/350?
(1)
Yuvraj said:
1 decade ago
Please could explane me how is come 50/3 ?
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