Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 10)
10.
In what ratio must water be mixed with milk to gain 16
% on selling the mixture at cost price?
% on selling the mixture at cost price?
Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1.
| S.P. of 1 litre of mixture = Re.1, Gain = | 50 | %. |
| 3 |
 C.P. of 1 litre of mixture = |
 |
100 x | 3 | x 1 |  |
= | 6 |
| 350 | 7 |
By the rule of alligation, we have:
| C.P. of 1 litre of water C.P. of 1 litre of milk | |||||
| 0 | Mean Price
| Re. 1 | |||
|
|
||||
| Ratio of water and milk = |
1 | : | 6 | = 1 : 6. |
| 7 | 7 |
Discussion:
51 comments Page 3 of 6.
Vishal said:
8 years ago
Here, c.p = ((100/(100+gain%))s.p),
Here 100 + gain% = >100 + 50/3 = 350/3,
100(3/350) * 1=300/350 = 6/7.
Here 100 + gain% = >100 + 50/3 = 350/3,
100(3/350) * 1=300/350 = 6/7.
Thakursaab said:
8 years ago
Let you are selling pure milk in 1 rs for each litre.
Now, someday you think to gain more money for this you take some milk out and replace it with water.
say ratio remains of milk to water =1 : x.
Now, you know that water is free hence it cost nothing and still you are able to sell the total 1 litre mixture in same price i.e,1 rs.
Hence
SP=1.
CP = portion of milk present in mixture=1/1+x.
Because you have to just pay for milk in case you purchase it.
Now use gain % formula: sp - cp/cp = (%gain/100).
You will get the answer by solving the equation.
Now, someday you think to gain more money for this you take some milk out and replace it with water.
say ratio remains of milk to water =1 : x.
Now, you know that water is free hence it cost nothing and still you are able to sell the total 1 litre mixture in same price i.e,1 rs.
Hence
SP=1.
CP = portion of milk present in mixture=1/1+x.
Because you have to just pay for milk in case you purchase it.
Now use gain % formula: sp - cp/cp = (%gain/100).
You will get the answer by solving the equation.
Pritam said:
8 years ago
I can't understand how 3/350 is coming? Can anybody help me? please.
Akshay said:
9 years ago
Simple method.
% always denote to 100.
So, 50/3 : 100 = 1/6.
% always denote to 100.
So, 50/3 : 100 = 1/6.
SUMIT VERMA said:
9 years ago
Let the cost price be Rs.100.
Since gain is Rs. 50/3.
So S.P is 100 + 50/3 = Rs.350/3.
Hence, Ratio = S.P - C.P/C.P, (350/3 - 100)/100 = 1/6.
Since gain is Rs. 50/3.
So S.P is 100 + 50/3 = Rs.350/3.
Hence, Ratio = S.P - C.P/C.P, (350/3 - 100)/100 = 1/6.
Tiger karim said:
9 years ago
According to question,
Millk = 100 ,
Water = 50/3,
Ratio = 50/3 : 100 = 1 : 6.
Millk = 100 ,
Water = 50/3,
Ratio = 50/3 : 100 = 1 : 6.
Sowmya said:
1 decade ago
Blindly assumed like this type problems.
16 2/35% = 50/3%.
So, 50/3/100 = 50/3*1/100 = 50/300 = 1/6.
So, 1:6.
16 2/35% = 50/3%.
So, 50/3/100 = 50/3*1/100 = 50/300 = 1/6.
So, 1:6.
Jose said:
1 decade ago
I can't understand 3/350.
Pratik said:
1 decade ago
It is the gain % so 100+ 50/3 = 350/3 and putting this into the formula we get 100/350/3 = 100*3/350
Raghaav said:
1 decade ago
can any one explain this sum please
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