Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 10)
10.
In what ratio must water be mixed with milk to gain 16
% on selling the mixture at cost price?

Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1.
S.P. of 1 litre of mixture = Re.1, Gain = | 50 | %. |
3 |
![]() |
![]() |
100 x | 3 | x 1 | ![]() |
= | 6 |
350 | 7 |
By the rule of alligation, we have:
C.P. of 1 litre of water C.P. of 1 litre of milk | |||||
0 | Mean Price
| Re. 1 | |||
|
|
![]() |
1 | : | 6 | = 1 : 6. |
7 | 7 |
Discussion:
51 comments Page 2 of 6.
Pari said:
7 years ago
CP+Profit=SP.
Profit gave =1/6.
SP of 1-litre mixture assumed to be Re1 and CP of 1-litre milk assumed to be Re1
CP+1/6 of CP = SP(which is assumed as 1).
So, CP comes out as 6/7.
Profit gave =1/6.
SP of 1-litre mixture assumed to be Re1 and CP of 1-litre milk assumed to be Re1
CP+1/6 of CP = SP(which is assumed as 1).
So, CP comes out as 6/7.
(1)
RIni said:
7 years ago
The amount of water =x litre.
Amount of milk= 100-x litre.
Profit= (x/(100-x))*100=50/3.
x=100/7=amount of water.
Amount of milk= 100-100/7=600/7.
The ratio of the amount of water to milk=1:6.
Amount of milk= 100-x litre.
Profit= (x/(100-x))*100=50/3.
x=100/7=amount of water.
Amount of milk= 100-100/7=600/7.
The ratio of the amount of water to milk=1:6.
(1)
Sathish said:
7 years ago
Can anyone explain why taking water : milk and not milk : water?
(1)
Nitish raja said:
6 years ago
Let cp of milk in% be = 100%,
So, milk : water = 100% : 16 2/3%,
100% : 50/3 = 1: 6.
So, milk : water = 100% : 16 2/3%,
100% : 50/3 = 1: 6.
(1)
Nadim miah said:
6 years ago
If 100 is cost price and sp then why do we add 50/3 with cp? Please explain.
(1)
Pidu said:
9 years ago
They have used C.P. formula.
C.P = (100/(100 + gain%) * S.P).
So, (100/(100 + (50/3)) * 1).
100 * (3/350) * 1.
C.P = (100/(100 + gain%) * S.P).
So, (100/(100 + (50/3)) * 1).
100 * (3/350) * 1.
Cosul said:
7 years ago
Let, 100 litres cost 100 rs.
Now, 100 + y litres cost 350/3 rs.
So re-arranging equations
100 --> 100.
100+y ---> 350/3.
Solving for y we get 16.33 litres.
So that means we add 16 litres more to 100 lit of milk.
So, the ratio is 16 /100 = 0.16.
Now, 100 + y litres cost 350/3 rs.
So re-arranging equations
100 --> 100.
100+y ---> 350/3.
Solving for y we get 16.33 litres.
So that means we add 16 litres more to 100 lit of milk.
So, the ratio is 16 /100 = 0.16.
Rohit Chaudhary said:
8 years ago
In what proportion must water be mixed with spirit to gain 9.09% by selling it at cost price. The quantity of water in the mixture of 1 litter is?
Can anyone help me to solve this question?
Can anyone help me to solve this question?
Paras said:
8 years ago
I too agree that it should be 5/6 instead of 6/7.
Same thing was done in 6th question where same logic was applied.
It gives ratio 1:5.
Please, anyone explain.
Same thing was done in 6th question where same logic was applied.
It gives ratio 1:5.
Please, anyone explain.
Milad said:
8 years ago
according to question.
The gaining % is 50/3.
so, the percent of water be 50/3.
And percent of milk 100.
so, W:m =1:6.
The gaining % is 50/3.
so, the percent of water be 50/3.
And percent of milk 100.
so, W:m =1:6.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers