Aptitude - Alligation or Mixture - Discussion

CP+Profit=SP.
Profit gave =1/6.
SP of 1-litre mixture assumed to be Re1 and CP of 1-litre milk assumed to be Re1
CP+1/6 of CP = SP(which is assumed as 1).
So, CP comes out as 6/7.

1/6=16 * 2/3%.

So take cost price is 100%.
and 1 : 1/6 = 6:1.

Let, 100 litres cost 100 rs.
Now, 100 + y litres cost 350/3 rs.
So re-arranging equations

100 --> 100.
100+y ---> 350/3.

Solving for y we get 16.33 litres.
So that means we add 16 litres more to 100 lit of milk.

So, the ratio is 16 /100 = 0.16.

In what proportion must water be mixed with spirit to gain 9.09% by selling it at cost price. The quantity of water in the mixture of 1 litter is?

Can anyone help me to solve this question?

I too agree that it should be 5/6 instead of 6/7.
Same thing was done in 6th question where same logic was applied.
It gives ratio 1:5.

Please, anyone explain.

according to question.

The gaining % is 50/3.
so, the percent of water be 50/3.
And percent of milk 100.
so, W:m =1:6.

How we get to know either they are asking milk to water ratio or water to milk ratio that's why it can be 6:1 and 1:6?

Here, c.p = ((100/(100+gain%))s.p),
Here 100 + gain% = >100 + 50/3 = 350/3,
100(3/350) * 1=300/350 = 6/7.

Let you are selling pure milk in 1 rs for each litre.

Now, someday you think to gain more money for this you take some milk out and replace it with water.
say ratio remains of milk to water =1 : x.

Now, you know that water is free hence it cost nothing and still you are able to sell the total 1 litre mixture in same price i.e,1 rs.

Hence
SP=1.
CP = portion of milk present in mixture=1/1+x.
Because you have to just pay for milk in case you purchase it.
Now use gain % formula: sp - cp/cp = (%gain/100).

You will get the answer by solving the equation.

I can't understand how 3/350 is coming? Can anybody help me? please.