# Aptitude - Alligation or Mixture - Discussion

### Discussion :: Alligation or Mixture - General Questions (Q.No.13)

13.

The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs. 20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is:

 [A]. Rs. 18 [B]. Rs. 18.50 [C]. Rs. 19 [D]. Rs. 19.50

Explanation:

Let the price of the mixed variety be Rs. x per kg.

By rule of alligation, we have:

 Cost of 1 kg of Type 1 rice Cost of 1 kg of Type 2 rice Rs. 15 Mean Price Rs. x Rs. 20 (20 - x) (x - 15) (20 - x) = 2 (x - 15) 3 60 - 3x = 2x - 30 5x = 90 x = 18.

 Nazira said: (Dec 7, 2010) what is the mixture ratio

 Narasimha said: (Jan 31, 2011) Hi this is also solve with, avg model formula: 2:3::type1:type2 type1 2 parts rs 15 perkg type2 3 parts rs 20per kg So that avg price = (15*2+20*3 )/5         //2+3=5 =90/5 =18

 Ranjith said: (Feb 24, 2011) Nazira The Mixture ratio suppose for a KG is 0.4 Kg of 15 Per/kg and 0.6 Kg of 20 Per/kg

 Kumaresh said: (Jul 27, 2013) Type 1 rice : Rs.15/kg. 2/5*15 = 2*3 = 6. Type 2 rice : Rs.20/kg. 3/5*20 = 3*4 = 12. The mixture worth is : 6+12 = Rs.18/kg.

 Message said: (Mar 15, 2014) I don't understand the rule of allegation. Can someone please explain it to me.

 Sankalp said: (Aug 11, 2014) Hey guys it can be more simple suppose. You took 2kg type1 and 3 kg type 2. Type1 cost is 3o Rs and type2 cost is 60Rs. So new mixture of 5 kg cost Rs 90. So 1kg = 18 Rs.

 Kasinath said: (Aug 12, 2014) Type1 Rice costs 15Rs/Kg. Type2 Rice costs 20Rs/Kg. Given that Type1 and Type2 are mixed in 2:3 ratio. Let us consider option [A] i.e., 18. ``` 15 20 18 => 20-18=2 18-15=3.``` Hence Option[A] 18 is the correct answer.

 Prasanna said: (Oct 7, 2014) Type 1 15rs and Type 2 20rs ratio is 2:3 so, Total 5 parts in which 2 parts type 1 and 3 parts type 2. = (2*15+3*20)/5. = 90/5. = 18rs.

 Sudharsan Madurai said: (Jan 2, 2015) HAI GUYS. SIMPLE WAY: (2:3). 15+3 = 18. 20-2 = 18.

 Anusha said: (Sep 21, 2016) According to the rule of the allegation, the cheaper (min) should be on the left side and dearer (max) on the right side. But why the principle is not used in the solutions?

 Lakshmi G said: (Oct 31, 2016) Please give the formula to solve the problem.

 Jitender Sehrawat said: (Dec 6, 2016) Simple see: you have two mixture one is 15kg and another is 20 kg and you have given they are in ratio 2:3. Its mean you have 20%of 15kg = 3 and 30%of 20kg = 6 When you will mix them it will be 6x3 = 18kg.

 Ishmeet said: (Aug 18, 2017) Simply (2(15)+3(20))/5=18.

 Amin said: (Jun 10, 2019) Not clear with the answer. Please explain me.

 Pooja said: (Oct 9, 2019) 2:3 Assume it to be 2 kg and 3kg. 2x15 = 30 and 20x3 = 60. 30+60 = 90. 90/2+3 = 18.

 Kajal said: (Jun 16, 2020) Type1(c) = 15rs ,type2(d)=20rs and ratio 2:3 find m. Using a formula : x/y=d-m/m-c: 2/3 = 20-m/m-15, 2(m-15) = 3(20-m), 2m + 3m = 60+30, 5m = 90, m = 18.

 Madhav said: (Mar 2, 2021) Given Type 1 cost = Rs. 15. Type 2 coat = Rs.20. And the resultant mixture ratio = 2 : 3. So to calculate Type 1 = 2/5 * 15 => 6/kg Type 2 cost = 3/ 5* 20 => 12 /kg. So 6 + 12 = 18/kg.