Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
481 comments Page 1 of 49.

Jayaprakash said:   5 days ago
How 13.89 came? Please explain to me.
(1)

Nether said:   1 week ago
It's 50 meters/second.

Nig said:   3 weeks ago
Thanks all for explaining it.
(3)

Joy said:   4 months ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(41)

Sonianenavath said:   4 months ago
Very Good Thanks.
(6)

Sanika prakash said:   5 months ago
Good answer. Thanks all for explaining the answer.
(12)

Aathisha Sadhasivam said:   6 months ago
How it 18÷5 will become? Please explain.

Here is the solution for this question:

The length of a train is given as 125m (here it is mentioned as m/s), and the speed is given as 5km/hr (here it is mentioned as km/hr).

While converting km/hr into m/s, we are multiplying the speed by 5/18; therefore while converting m/s into km/hr, we have to take the reciprocal of 5/18, that is 18/5. The speed of the train should be calculated in km/hr; therefore, we take 18/5.
(28)

Suja said:   6 months ago
How it 18÷5 will become? Please explain.
(14)

Preetilata Das said:   6 months ago
Someone, please explain this question properly.
(9)

Naveen reddy said:   7 months ago
125/10 = 12.5,
12.5 * 3.6 = 45,
45 + 5 = 50.
(31)


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