Aptitude - Problems on Ages - Discussion

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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?

[A].

[B].

[C].

[D].

[E].

Answer: Option D

Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

Dharumaraj S said: (Mon, Jun 7, 2010 10:20:30 PM)

(b-2)+ b + .5b =27 which is an alternate method to solve the same problem.....

Suresh said: (Wed, Jun 16, 2010 02:30:30 PM)

mr dharumaraj shall u plz explain ur ans

Shan said: (Sat, Aug 21, 2010 11:07:45 AM)

Hi, let c year is x then B is twice of C then, B=2x Then A is 2 years older then B, therefore now B=2x,Then A=2+B, that is A=2+2x Therefore sum up all the value:[(2+2x)for A,2x for B,x for C] therefore 2+2x+2x+x=27 5x+2=27 5x=27-2 5x=25 x=25/5 x=5 now B is directly linked with C rather then A Therefore B=2x where x=5 2*5=10 that'z it my frnd