Aptitude - Calendar

Why Aptitude Calendar?

In this section you can learn and practice Aptitude Questions based on "Calendar" and improve your skills in order to face the interview, competitive examination and various entrance test (CAT, GATE, GRE, MAT, Bank Exam, Railway Exam etc.) with full confidence.

Where can I get Aptitude Calendar questions and answers with explanation?

IndiaBIX provides you lots of fully solved Aptitude (Calendar) questions and answers with Explanation. Solved examples with detailed answer description, explanation are given and it would be easy to understand. All students, freshers can download Aptitude Calendar quiz questions with answers as PDF files and eBooks.

Where can I get Aptitude Calendar Interview Questions and Answers (objective type, multiple choice)?

Here you can find objective type Aptitude Calendar questions and answers for interview and entrance examination. Multiple choice and true or false type questions are also provided.

How to solve Aptitude Calendar problems?

You can easily solve all kind of Aptitude questions based on Calendar by practicing the objective type exercises given below, also get shortcut methods to solve Aptitude Calendar problems.

Exercise :: Calendar - General Questions

1. 

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A. Sunday
B. Saturday
C. Friday
D. Wednesday

Answer: Option C

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.


2. 

What was the day of the week on 28th May, 2006?

A. Thursday
B. Friday
C. Saturday
D. Sunday

Answer: Option D

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan.  Feb.   March    April    May 
(31 +  28  +  31   +   30   +   28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.


3. 

What was the day of the week on 17th June, 1998?

A. Monday
B. Tuesday
C. Wednesday
D. Thursday

Answer: Option C

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan.  Feb.   March    April    May      June 
(31 +  28  +  31   +   30   +   31   +   17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.


4. 

What will be the day of the week 15th August, 2010?

A. Sunday
B. Monday
C. Tuesday
D. Friday

Answer: Option A

Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.


5. 

Today is Monday. After 61 days, it will be:

A. Wednesday
B. Saturday
C. Tuesday
D. Thursday

Answer: Option B

Explanation:

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.




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