Verbal Reasoning - Seating Arrangement - Discussion

Discussion Forum : Seating Arrangement - Seating Arrangement 1 (Q.No. 2)
2.

There are 8 houses in a line and in each house only one boy lives with the conditions as given below:

  1. Jack is not the neighbour Siman.
  2. Harry is just next to the left of Larry.
  3. There is at least one to the left of Larry.
  4. Paul lives in one of the two houses in the middle.
  5. Mike lives in between Paul and Larry.

If at least one lives to the right of Robert and Harry is not between Taud and Larry, then which one of the following statement is not correct ?

Robert is not at the left end.
Robert is in between Simon and Taud.
Taud is in between Paul and Jack.
There are three persons to the right of Paul.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
320 comments Page 23 of 32.

Navneet Singh hans said:   9 years ago
1_2_3_4_5_6_7_8

S_R_J_T_J_P_M_L_H.

Akshara said:   9 years ago
Answers is correct.

The arrangement of houses are SRTJPMLH.

So, the answer is c.

Aminul Islam said:   9 years ago
Correct arrangement is H L M P J S R T.

Pritesh said:   9 years ago
Option C is correct.

One possible arrangement could be:.

H J L M P T R S.

Ramjapo kumar said:   9 years ago
C is correct.

The possible arrangement could be. H J L M P T R S.

DEVI said:   9 years ago
According to me, the answer is C.

The possible arrangement is HLMPJTRS.

DEVI said:   9 years ago
According to me, the answer is C.

The possible arrangement is HLMPJTRS.

Amit Choudhary said:   9 years ago
Option C is the right answer.

The actual sating arrangement is JHLMPTRS.

Mahendra kumar said:   9 years ago
C is correct HLMPJTRS.

Shankar said:   9 years ago
Option C is the correct answer if and only if "between" is interpreted such that X is between Y and Z if Y and Z are the immediate neighbors of X.

E.g. In configuration JHLMPTRS, M is between L and P, but M is not between L and T.

Were "between" interpreted in the looser sense, where X is between Y and Z if Y is anywhere on one side of X and Z is anywhere on the other side, then there are 3 possible combinations that would satisfy the 7 initial conditions as well as condition C.

* HSLMPRTJ
* HSLMPTRJ
* HRLMPSTJ


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