Verbal Reasoning - Direction Sense Test - Discussion
Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 12)
12.
A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
Answer: Option
Explanation:
Discussion:
39 comments Page 1 of 4.
Shivi said:
5 years ago
@All.
Let me explain it simply,
As in the answer pic (please see there) if we add the distances of AB and DC it would be 5 km(2+3) and the distances of BC and DE it would be 12km (10+2). Now, just extend AB and DE , we would get a point say F ( on their intersecting point). Now join A to E, we will get a right-angled triangle named triangle AFE.
Now by Pythagoras theorem, we will find out the line segment AE.
Hypotenuse^2= perpendicular^2 + base^2.
AE^2 = AF^2+ FE^2,
AE^2= 5^2 + 12^2,
AE^2= 25+144,
AE^2 = 169,
AE x AE= 13 x 13,
AE= 13.
So, 13 (option B) is the right answer.
Hope it helps
Let me explain it simply,
As in the answer pic (please see there) if we add the distances of AB and DC it would be 5 km(2+3) and the distances of BC and DE it would be 12km (10+2). Now, just extend AB and DE , we would get a point say F ( on their intersecting point). Now join A to E, we will get a right-angled triangle named triangle AFE.
Now by Pythagoras theorem, we will find out the line segment AE.
Hypotenuse^2= perpendicular^2 + base^2.
AE^2 = AF^2+ FE^2,
AE^2= 5^2 + 12^2,
AE^2= 25+144,
AE^2 = 169,
AE x AE= 13 x 13,
AE= 13.
So, 13 (option B) is the right answer.
Hope it helps
(54)
Manviya said:
4 years ago
How to solve this? Please explain me.
(13)
Irfana said:
7 years ago
Try making a big right-angled triangle from the Dia.
Now the base value will be 10+2 = 12 and the height will be 2+3= 5. Now use Pythagoras theorem. 5^2+ 12^2 . Hence answer.
Now the base value will be 10+2 = 12 and the height will be 2+3= 5. Now use Pythagoras theorem. 5^2+ 12^2 . Hence answer.
(9)
AKRAM said:
1 decade ago
Using Pythagoras theorem.
AC+CE = AE required solution.
To find AC, CE ?
(AC)^2 = (2)^2+(10)^2 = Square root of 104 = 10.19.
(CE)^2 = (3)^2+(2)^2 = Square root of 13 = 3.6.
So AC+CE = 13.79. But option gave 13.
Hope all of you got it.
AC+CE = AE required solution.
To find AC, CE ?
(AC)^2 = (2)^2+(10)^2 = Square root of 104 = 10.19.
(CE)^2 = (3)^2+(2)^2 = Square root of 13 = 3.6.
So AC+CE = 13.79. But option gave 13.
Hope all of you got it.
(3)
Gurwinder said:
4 years ago
Good, Thanks everyone for explaining the answer.
(3)
Krishna said:
9 years ago
Extend the diagram and make it rectangle so its sides will be 12 and 5 the apply formula you will get 13 as answer.
(3)
Viraj said:
6 years ago
Very nice explanation, Thanks @Nagendra Murthy.
(2)
Singh said:
7 years ago
I can't understand this. Please explain me.
(2)
Menaka said:
9 years ago
When to use Pythagoras theorem and when to just add the distance. Can some one explain the difference? By simply adding the answer is 12, by the theorem it's 13.
Logically, the distance he travelled towards north will not be considered when calculating the distance covered, am I right?
Logically, the distance he travelled towards north will not be considered when calculating the distance covered, am I right?
(1)
Teresa said:
9 years ago
Why are we using Pythagoras theorem here?
(1)
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