Verbal Reasoning - Direction Sense Test - Discussion
Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 12)
12.
A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
Answer: Option
Explanation:
Discussion:
40 comments Page 2 of 4.
Menaka said:
9 years ago
When to use Pythagoras theorem and when to just add the distance. Can some one explain the difference? By simply adding the answer is 12, by the theorem it's 13.
Logically, the distance he travelled towards north will not be considered when calculating the distance covered, am I right?
Logically, the distance he travelled towards north will not be considered when calculating the distance covered, am I right?
(1)
Teresa said:
9 years ago
Why are we using Pythagoras theorem here?
(1)
Sagar Swain said:
8 years ago
Take another letter let it be 'F', and connect it to B and D making a right angled triangle AFE. You'll able to know how Pythagoras has been applied here.
(1)
Siyali said:
8 years ago
Can anyone explain that why we have to apply Pythagoras theorem here to get the answer?
Please explain me.
Please explain me.
Suresh said:
10 years ago
Sir, here we use right angle triangle then we find individual triangles. So this is not correct I think.
Dibyanshu said:
5 months ago
Your approach is correct, but you should ask for displacement, not distance.
If you are asking for distance, then the answer will be 17.
If you are asking for distance, then the answer will be 17.
Kalpita Mhatre said:
9 years ago
If we assume short side be x then hypotenuse is (2x+6) and 3rd side is (2x+4).
By applying Pythagoras.
(2x+6)square = (2x+4)square + x square.
Finally, gives x square -8x-20 = 0.
Which gives x=10 and x= -2.
So, sides are 10, 24 and 26.
By applying Pythagoras.
(2x+6)square = (2x+4)square + x square.
Finally, gives x square -8x-20 = 0.
Which gives x=10 and x= -2.
So, sides are 10, 24 and 26.
Moksha Roopa Sri said:
3 months ago
These two form the two legs of a right triangle, with the straight-line distance from start as the hypotenuse.
Applying the Pythagorean theorem:
d = (North)2 + (East)2d.
= √{(North)^2 + (East)^2}d.
=(North)2 + (East)2.
d = 5^2 + 12^2,
= 25 + 144,
= 169d .
d = 13 km.
He is 13 km from the starting point.
Applying the Pythagorean theorem:
d = (North)2 + (East)2d.
= √{(North)^2 + (East)^2}d.
=(North)2 + (East)2.
d = 5^2 + 12^2,
= 25 + 144,
= 169d .
d = 13 km.
He is 13 km from the starting point.
Chandrika labh said:
10 years ago
Bit confusing, Somebody please mark it correct answer for sure.
Shivam said:
10 years ago
Nice, well said @Murali.
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