Verbal Reasoning - Direction Sense Test - Discussion

Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 12)
12.
A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
10 km
13 km
15 km
None of these
Answer: Option
Explanation:
Discussion:
39 comments Page 2 of 4.

Sagar Swain said:   8 years ago
Take another letter let it be 'F', and connect it to B and D making a right angled triangle AFE. You'll able to know how Pythagoras has been applied here.
(1)

Subha said:   8 years ago
If we don't get a perfect square number like the square root of 533.

Then what will be the answer, Is this 23 or none of these?
(1)

Nagendramurthy said:   1 decade ago
No. Here we have to find the shortest distance from a to e. so that can be find out like this..

Total distance travel towards north 2+3= 5km
Total distance travel towards east 10+2= 12km
Therefore the shortest distance will sqrt of (5*5+12*12) = sqrt(169) = 13
I think u got my point. Have a nice day.
(1)

Shivam said:   9 years ago
Nice, well said @Murali.

Chandrika labh said:   9 years ago
Bit confusing, Somebody please mark it correct answer for sure.

Puja Shil said:   10 years ago
Thanks, @Nagendra.

Raghavendra said:   9 years ago
I understand it clearly, thanks for the given explanation.

Kalpita Mhatre said:   9 years ago
If we assume short side be x then hypotenuse is (2x+6) and 3rd side is (2x+4).

By applying Pythagoras.
(2x+6)square = (2x+4)square + x square.
Finally, gives x square -8x-20 = 0.
Which gives x=10 and x= -2.
So, sides are 10, 24 and 26.

Siyali said:   8 years ago
Can anyone explain that why we have to apply Pythagoras theorem here to get the answer?

Please explain me.

Dibyanshu said:   2 months ago
Your approach is correct, but you should ask for displacement, not distance.

If you are asking for distance, then the answer will be 17.


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