Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 2 (Q.No. 3)
Directions to Solve
Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
3.
If dice (I), (II) and (III) have even number of dots on their bottom faces and the dice (IV), (V) and (VI) have odd number of dots on their top faces, then what would be the difference in the total number of top faces between there two sets?
Answer: Option
Explanation:
No. of faces on the top faces of the dice (I), (II) and (III) are 5, 1 and 5 respectively.
Therefore, Total of these numbers = 5 + 1 + 5 = 11
No. of dots on the top faces of the dice (IV), (V) and (VI) are 1, 3 and 1 respectively.
Therefore, Total of these numbers = 1 + 3 + 1 = 5
Required difference = 11 - 5 = 6
Discussion:
20 comments Page 1 of 2.
Shubhi said:
2 years ago
I think the right Answer is 5.
(4)
Rakesh Kumar das said:
2 years ago
According to question, the difference between the TOP faces i .e 11 - 5 = 6.
As dice(l),(ll),(lll) have sum of BOTTOM faces = 6 + 2 + 2 = 10.
As dice(l),(ll),(lll) have sum of BOTTOM faces = 6 + 2 + 2 = 10.
(3)
SRK said:
3 years ago
Answer should be 5.
(2)
Rohit said:
9 years ago
In question, it is given that 1,2,3 have even no of dots on them,then it must be 2, 6, 2 respectively, but it is given 1, 5, 1 in the answer.
According to question, the answer should be
= 2 + 6 + 2 - (1 + 3 + 1),
= 10 - 5,
= 5.
According to question, the answer should be
= 2 + 6 + 2 - (1 + 3 + 1),
= 10 - 5,
= 5.
(1)
Suchana said:
5 years ago
The right answer should be 5.
(1)
Suchana said:
5 years ago
The right answer should be 5.
(1)
JASWANT said:
4 years ago
@Rohit.
Even no of dots means 2, 6, 4 not 2, 6, 3.
Even no of dots means 2, 6, 4 not 2, 6, 3.
(1)
M.vanitha sreee said:
5 years ago
I can't understand these so anyone explain this concept.
Klins said:
2 weeks ago
Here, the question should be bottom of the faces for even numbers.
Dwiti Bajaj said:
1 year ago
The answer is 6 as we are asked to get the DIFFERENCE of the TOP faces of set 1 (i.e. 1, 2, 3) and set 2 (i.e. 4, 5, 6) and in the question we are given that in set 1 the BOTTOM faces are even so the TOP faces would be odd.
So in dices (1) the top face would contain 5, in dice (2) the top face would contain 1 and in dice (3) the top face would contain 5 so the total of set 1 would be 5+1+5= 11 and the total of set 2 would be 1+3+1=5.
So, the difference of TOP faces of both sets would be 11-5=6.
So in dices (1) the top face would contain 5, in dice (2) the top face would contain 1 and in dice (3) the top face would contain 5 so the total of set 1 would be 5+1+5= 11 and the total of set 2 would be 1+3+1=5.
So, the difference of TOP faces of both sets would be 11-5=6.
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