Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 2 (Q.No. 3)
Directions to Solve
Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
3.
If dice (I), (II) and (III) have even number of dots on their bottom faces and the dice (IV), (V) and (VI) have odd number of dots on their top faces, then what would be the difference in the total number of top faces between there two sets?
Answer: Option
Explanation:
No. of faces on the top faces of the dice (I), (II) and (III) are 5, 1 and 5 respectively.
Therefore, Total of these numbers = 5 + 1 + 5 = 11
No. of dots on the top faces of the dice (IV), (V) and (VI) are 1, 3 and 1 respectively.
Therefore, Total of these numbers = 1 + 3 + 1 = 5
Required difference = 11 - 5 = 6
Discussion:
19 comments Page 1 of 2.
Khushboo said:
1 decade ago
How to know about values & phases of dice?
Neha said:
1 decade ago
Can someone elaborate ?
Kaviya said:
9 years ago
Can someone explain how to solve these types of problems?
Rohit said:
9 years ago
In question, it is given that 1,2,3 have even no of dots on them,then it must be 2, 6, 2 respectively, but it is given 1, 5, 1 in the answer.
According to question, the answer should be
= 2 + 6 + 2 - (1 + 3 + 1),
= 10 - 5,
= 5.
According to question, the answer should be
= 2 + 6 + 2 - (1 + 3 + 1),
= 10 - 5,
= 5.
(1)
Maheah bambal said:
8 years ago
Yes, you are correct, Thanks @Rohit.
Utkarsh said:
7 years ago
Yes, you are correct @Rohit.
Chandana said:
5 years ago
@Rohit.
I didn't understand can you explain once more?
I didn't understand can you explain once more?
Anonymous said:
5 years ago
Anyone explain the answer in detail.
Suchana said:
5 years ago
The right answer should be 5.
(1)
Suchana said:
5 years ago
The right answer should be 5.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers