Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 1 (Q.No. 2)
2.
Two positions of dice are shown below. How many points will appear on the opposite to the face containing 5 points?
Answer: Option
Explanation:
In these two positions one of the common face having 1 point is in the same position. Therefore according to rule (2). There will be 4 points on the required face.
Discussion:
27 comments Page 2 of 3.
Renu adhikari said:
8 years ago
How will answer 4 while 5 point side face is 2 point?
Please explain.
Please explain.
Veerpal kaur said:
9 years ago
Here the sum of any two side of side is 7 so it is general dice and in case of general dice we have.
1 opposite to 6.
2 opposite to 5.
3 opposite to 4?
But it is following the rule of standard dice how? Aan anyone explain?
1 opposite to 6.
2 opposite to 5.
3 opposite to 4?
But it is following the rule of standard dice how? Aan anyone explain?
D!P said:
9 years ago
1 is same direction of two dice.
So 2 ----- 4 or 2 ---- 5.
So 2 ----- 4 or 2 ---- 5.
Surinder kumar said:
9 years ago
Please tell me rule 2.
Harshit said:
1 decade ago
Didn't get how it's solved.
Please tell what is rule 2?
Please tell what is rule 2?
Pk(praveenkumar) said:
10 years ago
What is rule no.2?
Explain the rule.
Explain the rule.
Shahid said:
10 years ago
How we can learn this kind of question I am trying to solve this kind of question, however this goes out of mind so please give me any suggestions.
Sateesh said:
10 years ago
Very simple:
Just strike the common numbers (2, 1) of both dice, then remaining numbers on the both dice are 5-4.
Just strike the common numbers (2, 1) of both dice, then remaining numbers on the both dice are 5-4.
Dorjay said:
1 decade ago
Earlier I was bit too confused about rule 2 now I understand.
It says If there are two common faces then and one is at common position then remaining faces (two faces left) that will be opposite to each other.
i.e In position 1 there are three faces 2 5 1. In position 2 there are three faces 4 2 1.
Two common faces (1 at common position and 2 not at common position) exactly fit in rule 2 description. So the remaining left is 5 and 4 they will be opposite to each other.
Total six faces in two position (3+3) = (1 2) & 5 + (1 2) & 4 common.
So 5 and 4 left they are opposite.
Only difference between rule 2 & rule 3 is that in rule 3 only one faces is common and that is at common position.
It says If there are two common faces then and one is at common position then remaining faces (two faces left) that will be opposite to each other.
i.e In position 1 there are three faces 2 5 1. In position 2 there are three faces 4 2 1.
Two common faces (1 at common position and 2 not at common position) exactly fit in rule 2 description. So the remaining left is 5 and 4 they will be opposite to each other.
Total six faces in two position (3+3) = (1 2) & 5 + (1 2) & 4 common.
So 5 and 4 left they are opposite.
Only difference between rule 2 & rule 3 is that in rule 3 only one faces is common and that is at common position.
Keerthana said:
1 decade ago
The question is opposite to face 5 points.
Lets see the both dices in points = 5, 2, 1 and 4, 2, 1. (all are nearest points right).
2 and 1 is common for both the dices.
4 only come to opposite side and so on 2 and 1 are already near to 5.
Hence 4 is the answer.
Lets see the both dices in points = 5, 2, 1 and 4, 2, 1. (all are nearest points right).
2 and 1 is common for both the dices.
4 only come to opposite side and so on 2 and 1 are already near to 5.
Hence 4 is the answer.
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