Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 1 (Q.No. 2)
2.
Two positions of dice are shown below. How many points will appear on the opposite to the face containing 5 points?
Answer: Option
Explanation:
In these two positions one of the common face having 1 point is in the same position. Therefore according to rule (2). There will be 4 points on the required face.
Discussion:
27 comments Page 1 of 3.
Harshit said:
1 decade ago
Didn't get how it's solved.
Please tell what is rule 2?
Please tell what is rule 2?
Pawan said:
1 decade ago
It is not cleared that how to follow rule 2 and not justified the answer how to get 4?
Abhishek vimal said:
1 decade ago
Tell me in detail how the answer 4 comes?
Siva Raman said:
1 decade ago
If face of 2 points is rotated to down, 5 points will go to bottom face, now 2 is in center and 4 is upper face. Hence 4 is opposite to 5.
Ajish said:
1 decade ago
In such question if 2 faces are common, remaining uncommon will be opposite to each other. It is proven. If you have doubt kindly search DSC'S Dice Lecture in you tube. All the best.
Pravin said:
1 decade ago
Explain me details?
Pravin said:
1 decade ago
Explain me details?
Deepak Allu said:
1 decade ago
ANS : D.
Consider the dice in figure 1. Hold the dice shown in figure in your hand such that the side having 5 points is facing you. Then on your right (adjacent to 5) we have 1, and the top side will be 2.
If you rotate the dice such that the side having 2 points is facing you, then we get the second figure.
Hence the answer is 4.
Consider the dice in figure 1. Hold the dice shown in figure in your hand such that the side having 5 points is facing you. Then on your right (adjacent to 5) we have 1, and the top side will be 2.
If you rotate the dice such that the side having 2 points is facing you, then we get the second figure.
Hence the answer is 4.
Keerthana said:
1 decade ago
The question is opposite to face 5 points.
Lets see the both dices in points = 5, 2, 1 and 4, 2, 1. (all are nearest points right).
2 and 1 is common for both the dices.
4 only come to opposite side and so on 2 and 1 are already near to 5.
Hence 4 is the answer.
Lets see the both dices in points = 5, 2, 1 and 4, 2, 1. (all are nearest points right).
2 and 1 is common for both the dices.
4 only come to opposite side and so on 2 and 1 are already near to 5.
Hence 4 is the answer.
Dorjay said:
1 decade ago
Earlier I was bit too confused about rule 2 now I understand.
It says If there are two common faces then and one is at common position then remaining faces (two faces left) that will be opposite to each other.
i.e In position 1 there are three faces 2 5 1. In position 2 there are three faces 4 2 1.
Two common faces (1 at common position and 2 not at common position) exactly fit in rule 2 description. So the remaining left is 5 and 4 they will be opposite to each other.
Total six faces in two position (3+3) = (1 2) & 5 + (1 2) & 4 common.
So 5 and 4 left they are opposite.
Only difference between rule 2 & rule 3 is that in rule 3 only one faces is common and that is at common position.
It says If there are two common faces then and one is at common position then remaining faces (two faces left) that will be opposite to each other.
i.e In position 1 there are three faces 2 5 1. In position 2 there are three faces 4 2 1.
Two common faces (1 at common position and 2 not at common position) exactly fit in rule 2 description. So the remaining left is 5 and 4 they will be opposite to each other.
Total six faces in two position (3+3) = (1 2) & 5 + (1 2) & 4 common.
So 5 and 4 left they are opposite.
Only difference between rule 2 & rule 3 is that in rule 3 only one faces is common and that is at common position.
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