Verbal Reasoning - Dice - Discussion

Discussion Forum : Dice - Dice 1 (Q.No. 2)
2.

Two positions of dice are shown below. How many points will appear on the opposite to the face containing 5 points?

3
1
2
4
Answer: Option
Explanation:
In these two positions one of the common face having 1 point is in the same position. Therefore according to rule (2). There will be 4 points on the required face.
Discussion:
27 comments Page 1 of 3.

Vaibhav Sharma said:   2 years ago
How to solve this question?

Can anyone tell me?
(8)

Prakash said:   4 years ago
Anyone, Please, explain me the Answer.
(6)

Antara Chowdhuri said:   4 years ago
In these two positions; 2 and 1 is common, 1 is common in the same position, therefore 4 is the opposite point of 5 here.
(9)

Bikram said:   7 years ago
It's wrong because one side of dice is general while other is standard, one dice can't be general and standard both.
(5)

Sanghamitra said:   7 years ago
Actually, there is a rule if two faces are common then pair that common two faces and remaining faces will opportunities to each other. In this case, there are two common faces in two dice that means in 1st dice there is 1 and 2 and in second dice there is 1 and 2 then in 1st dice 5 remain and in second dice 4 remain so opposite of 5 is 4.
(6)

Rahul Kumar said:   7 years ago
@All.

If you will rotate the first dice to make the position of no 2 = no 2 of the second dice the opposite face of no 5 will be 4.
(1)

Aryadrj said:   7 years ago
The common number will be canceled and the rest number will be opposite to each other.

11 and 22 will be cancel and 4 and 5 will be common.
(1)

Smruti said:   7 years ago
According to the rule,

In this case, if the two numbers are common in both the dices then the left number of 1st dice is opposite to the left number of 2nd dice.

In 1st and 2nd dice 2&1appear.
And rest 5&4so they are opposite to each other.

Renu adhikari said:   8 years ago
How will answer 4 while 5 point side face is 2 point?

Please explain.

Sahil indorkar said:   8 years ago
According to rule, when two faces of each dice are common. Another face are always common.

In 1st dice (2, 1 are appeared).
In 2nd dice (2, 1 are appeared).

Remaining are 5 and 4 so according to the rule, they are opposite to each other.
(2)


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